Spring Boot Security OAuth2 自定义异常消息

Question

我的 Spring Boot RESTfull 项目中有些特殊情况，而不是身份验证异常错误消息的标准定制。我需要不同的消息，具体取决于用户名或密码是否错误，或者用户名不存在，或者用户是否在数据库中被停用。目前我只能收到消息"Bad credentials"，我还没有找到任何解决方案如何根据某些用户属性或特殊情况自定义消息。

我目前有这样的自定义身份验证提供程序：

@Component
public class CustomAuthenticationProvider implements AuthenticationProvider {

    @Autowired
    private CustomUserDetailsService userDetailsService;

    @Autowired
    PasswordEncoder passwordEncoder;

    @Override
    public Authentication authenticate(Authentication authentication)
            throws org.springframework.security.core.AuthenticationException {


        String name = authentication.getName();
        String password = authentication.getCredentials().toString();

        UserDetails userDetails = userDetailsService.loadUserByUsername(name);


        if(passwordEncoder.matches(password, userDetails.getPassword())) {
            return new UsernamePasswordAuthenticationToken(userDetails.getUsername(), userDetails.getPassword(),
                    userDetails.getAuthorities());
        }

        return null;
    }

    @Override
    public boolean supports(Class<?> authentication) {
        return authentication.equals(UsernamePasswordAuthenticationToken.class);
    }


}

我有这样的自定义用户详细信息服务：

@Service
public class CustomUserDetailsService implements org.springframework.security.core.userdetails.UserDetailsService{

    @Autowired
    UserService userService; //my custom user service

    @Override
    public UserDetails loadUserByUsername(String username) {
        try {
            User user = userService.getUserByUsername(username);

            if(user == null) {
                throw new UsernameNotFoundException("Username doesn't exist");
            } else if(user.isDeactivated()) {
                throw new UsernameNotFoundException("User deactivated");
            }

            List<Authority> listOfAuthorities = userService.getAllAuthoritiesFromUser(user.getUserId());
            List<GrantedAuthority> grantedAuthorities = new ArrayList<>();

            for(Authority authority : listOfAuthorities) {
                grantedAuthorities.add(new SimpleGrantedAuthority(authority.getName()));
            }

            org.springframework.security.core.userdetails.User userNew =
            new org.springframework.security.core.userdetails.User(user.getUsername(), user.getPassword(), grantedAuthorities);
            return userNew;

        }
        catch(Exception ex) {
            throw new UsernameNotFoundException("Username or password not correct");
        }

    }
}

我在哪里可以处理来自throw new UsernameNotFoundException 的消息并将其返回为"error_description"？

编辑 这也是我的SecurityConfig 和ResourceServerConfig：

@Configuration
@EnableWebSecurity
@Order(Ordered.LOWEST_PRECEDENCE)
public class SecurityConfig extends WebSecurityConfigurerAdapter{

    @Autowired
    CustomUserDetailsService userDetailsService;

    @Autowired
    private CustomAuthenticationProvider authProvider;

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.authenticationProvider(authProvider)  
        .userDetailsService(userDetailsService)
        .passwordEncoder(passwordEncoder());
    }


    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.csrf().disable();
        http.addFilterBefore(new AuthenticationTokenFilter(authenticationManager()), BasicAuthenticationFilter.class);
    }

    // must be overriden and exposed as @Bean, otherwise boot's AuthenticationManagerConfiguration will take precedence
    @Bean @Override
    public AuthenticationManager authenticationManagerBean() throws Exception {
        return super.authenticationManagerBean();
    }

    @Bean
    public PasswordEncoder passwordEncoder() {
        return new BCryptPasswordEncoder();
    }
}

@Configuration
@EnableResourceServer
public class ResourceServerConfig extends ResourceServerConfigurerAdapter{

    @Autowired
    private AuthExceptionEntryPoint myEntryPoint;

    @Override
    public void configure(HttpSecurity http) throws Exception {
        http.anonymous().and().authorizeRequests().antMatchers("/**")
                .authenticated()
                .and()
                .exceptionHandling().authenticationEntryPoint(myEntryPoint).accessDeniedHandler(new OAuth2AccessDeniedHandler());
    }

}

Answer 1

Spring Security 上的这条通用消息是有目的的，它是为了混淆登录失败的实际原因。

一旦您根据需要提供特定消息，例如Username doesn't exist、User deactivated、Password incorrect 等等，你开始为恶意用户提供太多信息了。

更新

如果你仍然想这样做，你可以实现你自己的AuthenticationFailureHandler，这样的东西应该可以工作：

public class DefaultAuthenticationFailureHandler extends SimpleUrlAuthenticationFailureHandler {

        @Override
        public void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response, 
                                            AuthenticationException exception) throws IOException, ServletException {
            super.onAuthenticationFailure(request, response, exception);
            if (exception.getClass().isAssignableFrom(UsernameNotFoundException.class)) {
                response.sendRedirect("User not found")
            } else if (exception.getClass().isAssignableFrom(LockedException.class)) {
                response.sendRedirect("User Locked")
            }
        }
    }