【发布时间】:2012-01-09 01:28:08
【问题描述】:
我有以下头部函数:
float computeDistance3(Vector3f& vec_a, Vector3f& vec_b);
float computeDotProduct3(Vector3f& vecta, Vector3f& vectb);
float computeGeoDotProd3(Vector3f& vecta, Vector3f& vectb);
具有以下定义
float computeDistance3(Vector3f& vec_a, Vector3f& vec_b) {
float x = vec_a.x - vec_b.x;
float y = vec_a.y - vec_b.y;
float z = vec_a.z - vec_b.z;
return sqrt((x * x) + (y * y) + (z * z));
}
float computeDotProduct3(Vector3f& vec_a, Vector3f vec_b) {
return (vec_a.x * vec_b.x)
+ (vec_a.y * vec_b.y)
+ (vec_a.z * vec_b.z);
}
float computeGeoDotProd3(Vector3f& vecta, Vector3f& vectb) {
float amag, bmag, dotProd;
amag = vecta.computeMagnitude();
bmag = vectb.computeMagnitude();
dotProd = computeDotProduct3(vecta, vectb);
bool notZero = (amag != 0.0f && bmag != 0.0f) && dotProd != 0.0f;
if (notZero) {
return cosf(dotProd / (amag * bmag));
} else {
return -1.0f;
}
}
我知道他们的签名是一样的。这会让编译器感到困惑吗?我猜是这样,因为当我编译代码时,我得到了这个:
vector3f.cpp: In function ‘float computeGeoDotProd(Vector3f&, Vector3f&)’:
vector3f.cpp:139:43: error: call of overloaded ‘computeDotProduct3(Vector3f&, Vector3f&)’ is ambiguous
vector3f.cpp:139:43: note: candidates are:
vector3f.h:31:7: note: float computeDotProduct3(Vector3f&, Vector3f&)
vector3f.cpp:127:7: note: float computeDotProduct3(Vector3f&, Vector3f)
问题
解开编译器混乱的解决办法是什么?
【问题讨论】:
-
由于您的函数不会修改它们的参数,因此您应该通过 const 引用或值来获取它们。不是通过非常量引用。
标签: c++ function compiler-errors overloading