【发布时间】:2015-03-24 11:59:37
【问题描述】:
我的代码在 Eclipse 中运行时会编译,但是每当我尝试在命令提示符下运行它时,它都会抛出错误“无法找到或加载主类菜单”我已经坚持了好几个小时但仍然不知道如何解决它,以便任何帮助将不胜感激。 switch 语句调用不同类中的方法。
import java.util.Scanner;
import classSeperation.Frequency;
import classSeperation.InputFileAndString;
public class Menu {
public static String S="";
public static Scanner Scase = new Scanner(System.in);
//InputFileAndString inp= new InputFileAndString();
//Frequency FR= new Frequency();
public static void main(String[] args) {
Menu mnu= new Menu();
mnu.MainMenu();
}
public void MainMenu(){
System.out.println("Please enter a number");
System.out.println("Enter 0 to exit the program");
System.out.println("Enter 1 for inputting a file name");
System.out.println("Enter 2 for inputting a string");
System.out.println("Enter 3 for test 'I am a man frequency'");
S= Scase.nextLine();
Frequency FR= new Frequency();
switch(S){
default:
System.out.println("Please select a valid option");
MainMenu();
case "0":
System.out.println("Exiting program");
System.exit(0);
case "1":
InputFileAndString inp= new InputFileAndString();
inp.FileImp();
case "2":
FR.Freq();
break;
case "3":
FR.ManFreq();
break;
}
Scase.close();
}
public void SubMenuF(){
System.out.println("Please enter a number");
System.out.println("Enter 0 to exit");
System.out.println("Enter 1 for a graph result");
System.out.println("Enter 2 for character frequencies");
System.out.println("Enter 3 to return to Main Menu");
S= Scase.nextLine();
Frequency FR= new Frequency();
switch(S){
default:
System.out.println("This is not a valid option, please try again");
SubMenuF();
case "0":
System.out.println("Exiting program");
System.exit(0);
case "1":
FR.graph();
break;
case "2":
//Frequency
Frequency.frequencyFile();
break;
case "3":
MainMenu();
}
}
public void SubSubMenu(){
String S="";
Scanner Scase = new Scanner(System.in);
System.out.println("Please enter a number");
System.out.println("Enter 0 to exit the program");
System.out.println("Enter 1 for a graph");
System.out.println("Enter 2 to return to the main menu");
S= Scase.nextLine();
Frequency FR= new Frequency();
switch(S){
default:
System.out.println("This is not a valid option, please try again");
SubSubMenu();
break;
case "0":
System.out.println("Exiting program");
System.exit(0);
case "1":
FR.graph();
break;
case "2":
MainMenu();
}
Scase.close();
}
}
【问题讨论】:
-
你是如何在命令行上编译/运行它的?请记住,Eclipse 编译的文件与源文件不在同一目录中。
标签: java class compiler-errors runtime-error command-prompt