Jquery - 简单数组，如果项目不存在则推入，如果项目存在则移除项目答案

【问题标题】：Jquery - Simple Array, pushing item in if its not there already, removing item if it is thereJquery - 简单数组，如果项目不存在则推入，如果项目存在则移除项目
【发布时间】：2012-03-25 03:39:52
【问题描述】：

我正在构建一个简单的过滤系统，我只是想将一个字符串添加到一个数组中，并在单击链接时将其删除。我会尽量解释清楚..

$(document).ready(function(){
    //so I start with an empty array
    var filters [];
    //when a link is clicked I want to add it to the array..
    $('li a', context).click(function(e){
        //so I get the value held in the data-event attribute of the clicked item example: "john"
        newFilter = $(this).attr('data-event');
        //this is where I get stuck, I want to test to see if the string I now have
        //in 'newFilter' is in the array already or not.. if it is in the array I
        //want to remove it, but if it doesnt exist in the array i want to add it..
        if(jQuery.inArray(newFilter, filters){
            //add to array
        } else {
           //remove from array
        };
    e.preventDefault();
    });
});

【问题讨论】：

你可以尝试indexof你的字符串对数组吗？如果它返回-1 你push，如果它大于-1 你pop

标签： jquery arrays filter

【解决方案1】：

我可能是错的，但我相信这就像使用基本的 javascript 一样简单：_{[.push, .splice]}

if($.inArray(newFilter, filters)<0) {
    //add to array
    filters.push(newFilter); // <- basic JS see Array.push
} 
else {
    //remove from array
    filters.splice($.inArray(newFilter, filters),1); // <- basic JS see Array.splice
};

当然，如果你真的想简化它，你可以删除一些行并将其简化为内联编码。

0 > $.inArray(newFilter,filters) ? filters.push(newFilter) : filters.splice($.inArray(newFilter,filters),1);

对于 ABSOLUTE 纯 JS：

var i; (i=filters.indexOf(newFilter))<0?filters.push(newFilter):filters.splice(i,1);

分解：

var i;  //  Basic variable to be used if index of item exist
//  The following is simply an opening to an inline if statement.
//  It's wrapped in () because we want `i` to equal the index of the item, if found, not what's to follow the `?`.
//  So this says "If i = an index value less than 0".
(i=filters.indexOf(newFilter)) < 0 ?
    //  If it was not found, the index will be -1, thus push new item onto array
    filters.push(newFilter) : 
        //  If found, i will be the index of the item found, so we can now use it to simply splice that item from the array.
        filters.splice(i,1);

【讨论】：

@aendrew 我指的是方法内部的 wuts

【解决方案2】：

$.inArray() 如果找到则返回项目的索引，否则返回-1（就像indexOf() 在支持时所做的那样）。因此，您可以编写如下内容：

var found = jQuery.inArray(newFilter, filters);
if (found >= 0) {
    // Element was found, remove it.
    filters.splice(found, 1);
} else {
    // Element was not found, add it.
    filters.push(newFilter);
}

【讨论】：

【解决方案3】：

我发现的另一种方法：

删除：

filters = jQuery.grep(filters, function(value) {
  return value != newFilter;
});

添加：

filters.push(newFilter)

【讨论】：

【解决方案4】：

除非您有使用数组的特定原因，否则我建议您改用对象。

$(document).ready(function(){
    //so I start with an empty array
    var filters {};
    //when a link is clicked I want to add it to the array..
    $('li a', context).click(function(e){
        //so I get the value held in the data-event attribute of the clicked item example: "john"
        newFilter = $(this).attr('data-event');
        //this is where I get stuck, I want to test to see if the string I now have
        //in 'newFilter' is in the array already or not.. if it is in the array I
        //want to remove it, but if it doesnt exist in the array i want to add it..
        if (filters.hasOwnProperty(newFilter)) {
           // remove from object
           delete filters[newFilter];
        } else {
           //add to object
           filters[newFilter] = 'FOO'; // some sentinel since we don't care about value 
        };
    e.preventDefault();
    });
});

【讨论】：

嘿 jbabey .. 一个新手问题我如何使用 console.log 查看对象中的内容？目前我得到 - [object Object]
console.log(myObject.propName) 或 console.log(myObject['propName'])

【解决方案5】：

类似的东西？

var filters = [];
// ...
var newFilter = '...';
if(-1 !== (idx = jQuery.inArray(newFilter, filters))) {
   // remove
   filters.splice(idx, 1);
} else {
   // add
   filters.push(newFilter);
}

【讨论】：

【解决方案6】：

你可以使用lodash函数“xor”：

_.xor([2, 1], [2, 3]);
// => [1, 3]

如果您没有数组作为第二个参数，您可以简单地将变量包装到数组中

var variableToInsertOrRemove = 2;
_.xor([2, 1], [variableToInsertOrRemove]);
// => [1]
_.xor([1, 3], [variableToInsertOrRemove]);
// => [1, 2, 3]

这是文档：https://lodash.com/docs/4.16.4#xor

【讨论】：