【发布时间】：2016-06-15 00:10:43
【问题描述】：
我有一个在 SPARC T1 RTL 代码上运行的 SPARC 汇编文件（通过汇编程序将其转换为内存映像）。但我需要知道 RTL 正在执行多少条指令。无法手动计算文件中的指令数。如果您能向我展示一种方法，我将不胜感激......
由于文件很大，我附上 Dropbox 链接： https://dl.dropboxusercontent.com/u/48635184/exu_muldiv.s
但这里是前几行代码：
/***********************************************************************
* Name: exu_muldiv.s
* Date: April 23, 2003
*
* Description: Execute Mulx, Mulscc, Smul, Smulcc, Umul, Umulcc,
* Sdiv, Sdivcc, Sdivx, Udiv, Udivcc, Udivx with interesting data
* patterns in multiple threads. Also play with delay slots and
* intermixed mul and div operations.
*
* This test depends on SAS for result checking.
*
**********************************************************************/
! be sure to update when adding cases...
#define NUM_MUL_CASES 6
#define NUM_DIV_CASES 4
#define NUM_IMMED_CASES 5
! for divide by zero cases
#define H_T0_Division_By_Zero
#define My_T0_Division_By_Zero \
rdpr %tstate, %i1; \
rdpr %tt, %i1; \
rdpr %tpc, %i0; \
rdpr %tnpc, %i1; \
done; \
nop;
/*******************************************************/
#include "boot.s"
.global main
main:
th_fork(th_main,%l0) ! start up to four threads.
! All threads do the same thing, but with different data patterns.
! No need to run more than one core.
th_main_0:
setx mul_data_t0,%g7,%g1
ba all_threads1
nop
th_main_1:
setx mul_data_t1,%g7,%g1
ba all_threads1
nop
th_main_2:
setx mul_data_t2,%g7,%g1
ba all_threads1
nop
th_main_3:
setx mul_data_t3,%g7,%g1
ba all_threads1
nop
all_threads1:
!*************************************************************
! Operand2 as a register: MULX, UMUL, SMUL, UMULcc, SMULcc
!*************************************************************
add %g0,NUM_MUL_CASES,%g2
mova %icc,%g1,%g3 ! keep the multiply operand address handy
mul_loop1:
ldx [%g1],%l1
ldx [%g1+8],%l2
wr %g0,%g0,%ccr ! ccr clear
mulx %l1,%l2,%l4
umul %l1,%l2,%l5
rd %y,%i1 ! be sure SAS looks at Y-reg
smul %l1,%l2,%l6
rd %y,%i1
wr %g0,%g0,%ccr ! clear ccr
umulcc %l1,%l2,%l7
rd %y,%i1
wr %g0,%g0,%ccr
smulcc %l1,%l2,%l6
rd %y,%i1
wr %g0,0xff,%ccr ! set ccr. Should not matter.
umulcc %l1,%l2,%l7
rd %y,%i1
wr %g0,0xff,%ccr
smulcc %l1,%l2,%l6
rd %y,%i1
sub %g2,0x1,%g2
brnz,pt %g2,mul_loop1
add %g1,0x10,%g1 ! move operand pointer
!**********************************
! Operand2 as a register: MULScc
!**********************************
#ifndef MULSCC_BUGS
mova %icc,%g3,%g1 ! same ops as mul_loop1
add %g0,NUM_MUL_CASES,%g2
mulscc_1:
wr %g0,%g0,%ccr ! ccr clear
ldx [%g1],%l1
ldx [%g1+8],%l2
wr %l1,0,%y ! lower bits of multiplier into Y-reg
rd %y,%l0 ! for sas debug
srl %l1,0,%l1 ! clear rs1 upper
srl %l2,0,%l2 ! clear rs2 upper
mulx %l1,%l2,%l4 ! save for later compare
add %g0,0,%l1 ! clear rs1 (product upper) completely
add %g0,32,%l3 ! bit position counter
mulscc_2:
sub %l3,1,%l3
mulscc %l1,%l2,%l1
brgez,pt %l3,mulscc_2
nop
sllx %l1,33,%l1 ! product upper
rd %y,%l3 ! product lower
or %l1,%l3,%l3 ! full product should be equal to mulx
subcc %l3,%l4,%l5
tnz T_BAD_TRAP
nop
sub %g2,0x1,%g2
brnz,pt %g2,mulscc_1
add %g1,0x10,%g1 ! move operand pointer
#endif
!****************************************
! Operand2 as a register: SDIVX, UDIVX
!****************************************
rdth_id ! get thid in %o1
cmp %o1,0
be th_divx_0
cmp %o1,1
be th_divx_1
cmp %o1,2
be th_divx_2
nop
ba th_divx_3 ! if there are more than 4 threads...
nop
th_divx_0:
setx divx_data_t0,%g7,%g1
ba all_threads2
nop
th_divx_1:
setx divx_data_t1,%g7,%g1
ba all_threads2
nop
th_divx_2:
setx divx_data_t2,%g7,%g1
ba all_threads2
nop
th_divx_3:
setx divx_data_t3,%g7,%g1
ba all_threads2
nop
all_threads2:
add %g0,NUM_DIV_CASES,%g2
divx_loop1:
ldx [%g1],%l1
ldx [%g1+8],%l2
wr %g0,%g0,%ccr ! ccr clear
sdivx %l1,%l2,%l3
udivx %l1,%l2,%l4
sdivx %l2,%l1,%l5 ! use each operand as divisor and dividend
udivx %l2,%l1,%l6
sub %g2,0x1,%g2
brnz,pt %g2,divx_loop1
add %g1,0x10,%g1 ! move operand pointer
【问题讨论】：
-
我想知道你是否可以在某个模拟器中运行它，是否可以破解模拟器来给你运行指令的数量（如果这没有意义，请原谅我）
-
所以你需要动态指令计数（执行的指令总数），而不是静态 insn 计数（文件中的总 insn；循环内的 insn 仍然只计算一次。即代码大小）？
-
@Leo，你说得对，我在 VCS Simulator 上运行它，但我只是不知道如何/在哪里做。
-
@PeterCordes，静态指令可以让我很好地了解程序的大小，但是什么是计算指令总数（静态）的有效方法，然后我可以简单地将它与获取文件中需要执行的总指令的循环数。
-
您的一些指令在循环之外，所以这只是一个粗略的近似值，只有在您知道每个循环的迭代次数时才有效。无论如何，IDK如何。也许组装它并计算字节数，因为 SPARC 是具有固定大小指令的 RISC 机器。或者 assemble->disassemble 和 count lines（这会从 cmets 和标签中删除源代码行数）。
标签： assembly