【问题标题】:Syntax error, missing symbol in Basic语法错误,Basic 中缺少符号
【发布时间】:2013-05-30 14:56:21
【问题描述】:

您好,每次我尝试运行以下程序时:

L=-1
OPEN "tty.usbserial-FTG7QLFS:300,N,8,1,CS0,DS" FOR OUTPUT AS #1
WHILE L
    J=63
    MENU:   PRINT
        PRINT
        PRINT
        PRINT
        PRINT
        PRINT

    PRINT "WAITING FOR KEYSTROKE COMMAND"
        PRINT "TYPE:"
        PRINT "  C-CLOSE SHUTTER"
        PRINT "  O-OPEN SHUTTER"
        PRINT "  R-RESET CONTROL"
        PRINT "  Q-TERMINATE PROGRAM"
        PRINT
        PRINT

    START:
    A$ = INKEY$
    IF A$ = "O" THEN
        PRINT #1,CHR$(J+1);
        PRINT "SHUTTER OPEN COMMAND SENT"
        GOSUB TIMEOUT
        GOTO MENU
        ELSEIF A$ = "C" THEN
            PRINT #1,CHR$(J+2);
            PRINT "SHUTTER CLOSE COMMAND SENT"
            GOSUB TIMEOUT
            GOTO MENU
        ELSEIF A$ = "R" THE
            PRINT #1,CHR$(J+3);
            PRINT "CONTROL RESET COMMAND SENT"
            GOSUB TIMEOUT
            GOTO MENU
        ELSEIF A$ = "Q" THEN
            L = 0
            PRINT "PROGRAM TERMINATED"
        ELSE GOTO START
    END IF
WEND
END
TIMEOUT:    FOR I=1 TO 100:NEXT I
             CLS 0
             RETURN

我收到以下错误“语法错误,第 6 行缺少符号”,但在第 6 行只有一个打印语句,所以我无法弄清楚我缺少什么。我在 Mac OS X 上通过 Chipmunk Basic 运行程序。

谢谢

【问题讨论】:

    标签: syntax-error basic missing-symbols


    【解决方案1】:

    我猜

    OPEN "tty.usbserial-FTG7QLFS:300,N,8,1,CS0,DS" AS#1
    

    缺少文件访问模式。也许编译器正在寻找这样的标记但没有成功,并在接下来的几行中放弃了。

    Chipmunk BASIC 文档说:

    open STRINGEXPR for { input|output|append } as # FNUM
    -- or --
    open STRINGEXPR for random as # FNUM len = VAL
    

    http://anoved.net/cbasdox/statements.html#open

    我不太了解 Chipmunk BASIC,但在其他 BASIC 方言(QBasic、FreeBASIC、VisualBASIC Classic 等)中,您必须说明要打开文件的操作。

    FreeBASIC 示例:

    OPEN SomeFile FOR INPUT AS #1     ' input (read-only)
    OPEN OtherFile FOR OUTPUT AS #2   ' write (replace existing file)
    OPEN FooFile FOR BINARY AS #3     ' binary (read + write)
    

    这就像在 C-ish 语言中使用 fopen 时指定“r”、“r+”、...一样。

    【讨论】:

    • 也许它甚至就像他没有'空间'那样简单...... AS#1也许应该是AS#1
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