【发布时间】:2020-02-22 02:57:56
【问题描述】:
我有一个示例程序来熟悉 mysqlclient API。但是,当我静态编译并将其链接到 mysqlclient 库(.a 文件)时,链接器抱怨它找不到该文件,尽管它存在于我的路径中。链接到共享库(我的 Mac 上的.dylib 文件)有效。
请帮助我了解这种行为。非常感谢!
这是我的驱动程序client.c,它调用了mysqlclient 库。
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <mysql.h>
int main(int argc, char **argv)
{
MYSQL *mysql = NULL;
if (mysql_library_init(argc, argv, NULL)) {
fprintf(stderr, "could not initialize MySQL client library\n");
exit(1);
}
mysql = mysql_init(mysql);
if (!mysql) {
puts("Init faild, out of memory?");
return EXIT_FAILURE;
}
if (!mysql_real_connect(mysql, /* MYSQL structure to use */
NULL, /* server hostname or IP address */
NULL, /* mysql user */
NULL, /* password */
NULL, /* default database to use, NULL for none */
0, /* port number, 0 for default */
NULL, /* socket file or named pipe name */
CLIENT_FOUND_ROWS /* connection flags */ )) {
puts("Connect failed\n");
} else {
const char *query = "SELECT VERSION()";
if (mysql_real_query(mysql, query, strlen(query))) {
printf("Query failed: %s\n", mysql_error(mysql));
} else {
puts("Query OK");
}
}
mysql_close(mysql);
mysql_library_end();
return EXIT_SUCCESS;
}
这是我的编译方法
gcc -I /usr/local/Cellar/mysql/8.0.16/include/mysql client.c -L /usr/local/Cellar/mysql/8.0.16/lib/ -l mysqlclient.a
ld: library not found for -lmysqlclient.a
clang: error: linker command failed with exit code 1 (use -v to see invocation)
没有.a 的编译成功,因为它链接到共享库,而不是静态库。
最后,这是我的库文件:
ls /usr/local/Cellar/mysql/8.0.16/lib/libmysqlclient*
/usr/local/Cellar/mysql/8.0.16/lib/libmysqlclient.21.dylib /usr/local/Cellar/mysql/8.0.16/lib/libmysqlclient.a /usr/local/Cellar/mysql/8.0.16/lib/libmysqlclient.dylib
【问题讨论】:
标签: mysql c linker static-linking dynamic-linking