使用 Spring Boot webclient 反序列化 OffsetDateTime

Question

在为我的 web 服务编写测试用例时，我遇到了与 OffsetDateTimeStamp 相关的问题。当我从浏览器测试时，它会给出正确的响应，但是在编写测​​试用例时它没有显示偏移量，因此它失败了。

@SpringBootTest(webEnvironment = SpringBootTest.WebEnvironment.RANDOM_PORT)
public class TestControllerTest {

    @LocalServerPort
    private int port;
    private WebClient client;
    
    @Test
    public void test() {
        Person person = new Person();
        person.setId(1);
        person.setBirthDate(OffsetDateTime.now());
        person.setMobile(9090909090L);
        person.setName("Tempo");
        client = WebClient.create("http://localhost:"+port);
        Person response = client.post().uri("/test1")
                .contentType(MediaType.APPLICATION_JSON)
                .accept(MediaType.APPLICATION_JSON)
                .body(BodyInserters.fromValue(person))
                .retrieve()
                .bodyToMono(Person.class)
                .block();
        
        Assertions.assertEquals(person.getBirthDate(), response.getBirthDate());
    }
}

控制器代码

@RestController
public class TestController {

    @PostMapping("/test1")
    public Mono<Person> test1(@RequestBody Person person) {
        System.out.println(person.getBirthDate());
        return Mono.just(person);
    }
}

邮件申请代码

@SpringBootApplication
public class TestAppApplication {

    public static void main(String[] args) {
        SpringApplication.run(TestAppApplication.class, args);
    }

    @Bean
    public Module javaTimeModule() {
        return new JavaTimeModule();
    }

    @Bean
    public Jackson2ObjectMapperBuilderCustomizer jacksonObjectMapperCustomization() {
        return jacksonObjectMapperBuilder -> jacksonObjectMapperBuilder.timeZone(TimeZone.getDefault());
    }
}

Person.java

public class Person {
    
    private int id;
    private String name;
    private long mobile;
    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSXXX")
    private OffsetDateTime birthDate;
    public Person() {}
}

application.properties

spring.jackson.serialization.write-dates-as-timestamps=false
spring.jackson.deserialization.adjust-dates-to-context-time-zone=false
spring.jackson.serialization.write-dates-with-zone-id=true

测试用例的输出

org.opentest4j.AssertionFailedError: 
Expected :2021-01-04T17:43:51.817+05:30
Actual   :2021-01-04T12:13:51.817Z
<Click to see difference>

Answer 1

您的属性birthDate 在您的Person 实体类中是如何定义的？您需要在那里定义格式。你可以这样做：

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private OffsetDateTime birthDate;
...
public OffsetDateTime getBirthDate() {
    return birthDate;
}

在这个问题的答案中查看更多详细信息：Spring Data JPA - ZonedDateTime format for json serialization