C ++ getline无法接受输入

Question

我想读一个句子来解读，但是出了点问题。当我不输入任何字符时，它会打印出“The sentence is”和“Decoded sentence is”，但是当我输入一个或多个字符时，它只会坐在那里什么都不做。我不认为这可能是 MySentence 类的错误，因为它甚至不打印“The sentence is”。

#include <iostream>
#include <stdio.h>
#include "MySentence.h"
#include "Corpus.h"
#include <string>
using namespace std;

int main() {
    Corpus corp;
    std::cout << "The proportions are: ";
    for(int i = 0; i<26; i++) {
            cout << corp.proportion(i+97) <<", ";
    }
    cout << endl;
    cout << "Enter sentence terminated by <ENTER> ";

    string s= "";
    getline(cin, s);
    cout << "The sentence is " << s;
    MySentence sent(s);
    sent.decode(corp);
    cout << endl << "Deoded sentence is: " << sent.sentence;
    return 0;
}

Answer 1

按照 n.m. 的建议。尝试在行尾添加 endl

cout

因为缓冲区可能没有被刷新并且问题出在 MySentence 类中。

可能有帮助的有趣帖子是 Buffer flushing: "\n" vs. std::endl