Python子进程nmap输出不同于终端命令

Question

我正在尝试在 linux 中使用 nmap 命令的输出（shell 输出）：

sudo nmap -sn 192.168.1.0/24
------
Nmap scan report for 192.168.1.98
Host is up (0.094s latency).
MAC Address: B8:27:EB:CE:0A:9F (Raspberry Pi Foundation)

在 python 脚本中通过子进程：

import subprocess
p = subprocess.Popen(["nmap", "-sn", "192.168.1.0/24"], stdout=subprocess.PIPE)
output, err = p.communicate()
print ("*** Running nmap -sn 192.168.1.0/24 ***\n", output)

除了我需要 shell 输出具有的 MAC 行而 subprocess 不需要这一事实之外，这非常有效。

子进程输出：

\nNmap scan report for 192.168.1.98\nHost is up (0.015s latency).\n

我正在研究通过 MAC/名称获取 IP 的想法，如果没有那条线，我看不到如何做...

Answer 1

在python中不需要将nmap作为子进程运行，只需安装nmap库并导入即可。

pip install python-nmap

然后编写你的代码：

import json
import nmap

np = nmap.PortScanner()

target = '192.168.1.0/24'

# Scan the subnet 
results = np.scan(hosts=target, arguments='-sn')

# Clean the data nmap returns
results = results['scan']
output = {}
for result in results:
    output[result] = {}
    # Add the MAC addr to the IP
    try:
        output[result]['mac']       = results[result]['addresses']['mac']
    except:
        output[result]['mac']       = 'No MAC address avalible'
    # Add the vendor to the IP
    try:
        output[result]['vendor']    = list(results[result]['vendor'].values())[0]
    except:
        output[result]['vendor']    = 'No vendor info avalible'

print(json.dumps(output,indent=2))

当您运行代码时，您必须以 sudo 运行它，否则您将无法获得 MAC 地址。

输出应该是这样的

{
  "192.168.1.1": {
    "mac": "16:91:82:xx:xx:xx",
    "vendor": "No vendor info avalible"
  },
  "192.168.1.10": {
    "mac": "44:39:C4:xx:xx:xx",
    "vendor": "Universal Global Scientific Industrial"
  },
  "192.168.1.50": {
    "mac": "No MAC address avalible",
    "vendor": "No vendor info avalible"
  }
}

希望对你有帮助:-)