如何将 cout 的输出存储到变量中

Question

我正在制作一个 C++ 程序来根据你的父母估计你的身高。我想做它，这样我就可以输出英尺和英寸的高度。我不知道如何将 cout 的输出存储在

if (boygirl == "boy") {
    cout <<"Your estimated height is " << (mom *13/12 + dad) / 2  << " inches";
} and   else if (boygirl == "girl") {
    cout <<"Your estimated height is " << (dad+12/13 + mom) / 2   <<" inches";

到一个变量中，这样我就可以从变量中获取数据并使用它，而不是在上一步中询问英寸的结果。

您可能需要运行代码才能明白我的意思。 如果您不明白我的意思，请随时发表评论。

#include <iostream>
#include <string>

using namespace std;

void Convert(int inch) {
    int feet, inches;
    inches = inch % 12;
    feet = inch / 12;
    cout << "\n\t\tThe height in feet is " << feet << "\'" << inches << "\" " << endl;
}

int main() {
    int i = 0;
    do {
        float mom;
        float dad;
        string doyouwish;
        string boygirl;

        cout << " \n\nWELCOME TO THE C++ HEIGHT PREDICTION PROGRAM";
        cout << "\n\n INPUT GENDER TO BEGIN boy/girl: ";
        cin >> boygirl;

        cout << "How tall is your mother in inches: ";
        cin >> mom;
        cout << "How tall is your father in inches: ";
        cin >> dad;

        if (boygirl == "boy") {
            cout << "Your estimated height is " << (mom * 13 / 12 + dad) / 2 << " inches";
        } else if (boygirl == "girl") {
            cout << "Your estimated height is " << (dad + 12 / 13 + mom) / 2 << " inches";
        }

        int htInches;
        // Ask height from user
        cout << "\n\ntEnter height in Inches from the previous results: ";
        cin >> htInches;

        Convert(htInches);
        cout << "\n\n\n";

        ++i;
    } while (i < 10);
}

Answer 1

您是否正在寻找这样的东西：

int htInches = 0;
if (boygirl == "boy") {
  htInches = (mom * 13 / 12 + dad) / 2;
} else if (boygirl == "girl") {
  htInches = (dad + 12 / 13 + mom) / 2;
}
cout << "Your estimated height is " << htInches << " inches";

计算结果，将其存储在变量中，然后打印出来。