【发布时间】:2011-09-14 09:05:12
【问题描述】:
我有一个 SQL 服务器数据库,我从中提取日期并将 timestamp_t 的类型转换为 Int64,如下所示:
Int64 from_timestamp_t(dtl::timestamp_t& t)
{
// create a new posix time structure
boost::posix_time::ptime pt
(
boost::gregorian::date ( t.year, t.month, t.day),
boost::posix_time::time_duration ( t.hour, t.minute, t.second, t.fraction )
);
ptime epoch(date(1970, Jan, 1));
boost::posix_time::time_duration fromEpoch = pt - epoch;
// return it to caller
return fromEpoch.total_milliseconds();
}
我尝试从 Int64 转换回 boost ptime:
ptime from_epoch_ticks(Int64 ticksFromEpoch)
{
ptime epoch(date(1970, Jan, 1), time_duration(0,0,0));
ptime time = epoch + boost::posix_time::milliseconds(ticksFromEpoch);
return time;
}
出于某种原因,我不知道为什么,我的日期、时间等都是正确的,但我的分钟数比应有的值提前了几分钟。是因为数据库中的时间戳以秒为单位,而我使用的是毫秒吗?我该如何解决这个问题?
按照 Dan 的建议应用以下修改似乎已经解决了问题:
Int64 from_timestamp_t(dtl::timestamp_t& t)
{
int count = t.fraction * (time_duration::ticks_per_second() % 1000);
boost::posix_time::ptime pt
(
boost::gregorian::date ( t.year, t.month, t.day ),
boost::posix_time::time_duration ( t.hour, t.minute, t.second, count )
);
ptime epoch(date(1970, Jan, 1), time_duration(0, 0, 0, 0));
boost::posix_time::time_duration fromEpoch = pt - epoch;
return fromEpoch.total_milliseconds();
}
【问题讨论】:
-
丹的回答成功了,我在上面修改了我的解决方案
标签: c++ sql-server-2005 boost-date-time dtl-cpp