Spring Boot Maven 和 MySQL 错误处理

Question

我有以下 Spring Boot MySQL 查询：

visitorrepository.save(newvisitor)

在执行此 MySQL 查询时，我想以以下格式返回成功 JSON 或失败 JSON：

成功状态：

{
    "success": true,
    "message": "Some Helpful Message",
    "data": { } //This would be the newvisitor JSON that includes the primary key (id)
}

故障状态：

{
    "success": false,
    "message": "Some Helpful Message",
    "error_code": "404", // This should be whatever error number was returned
    "data": { } //This would be the newvisitor JSON that does not include the primary key (id)
}

在角度上，响应被捕获如下

this.http.post('http://localhost:8080/v1/api/post', this.visitor.value).toPromise().then((response:any) => { 
      console.log(response);
   })

post.java

@CrossOrigin(origins = "http://localhost:4200")
@RestController
public class post {

    @Autowired
    visitorrepository visitorrepository;

    @PostMapping("/v1/api/post")
    public void insert(@Valid @RequestBody newvisitor newvisitor) {
       try {
            visitorrepository.save(newvisitor);
            return // Success State JSON
        } catch () {
            return // Error State JSON
        }
    }
}

newvisitor.java

@Getter
@Setter
@Entity
@Table(name = "visitors")
public class newvisitor {

    @Id
    @GeneratedValue
    private Long id;
    @Size(min=1, max=250)
    @NotBlank
    private String firstname;
    @NotBlank
    private String lastname;
    @NotBlank
    private String month;
    @NotBlank
    private String day;
    @NotBlank
    private String year;
    @NotBlank
    private String socialsecuritynumber;
    @NotBlank
    private String street1;
    private String street2;
    @NotBlank
    private String city;
    @NotBlank
    private String state;
    @NotBlank
    private String zip;
    @NotBlank
    private String phone;
    @Email
    @NotBlank
    private String email;

    public newvisitor(){
        super();
    }
    public newvisitor(String firstname, String lastname, String month, String day, String year, String socialsecuritynumber, String street1, String street2, String city, String state, String zip, String phone, String email) {
        super();

        this.firstname = firstname;
        this.lastname = lastname;
        this.month = month;
        this.day = day;
        this.year = year;
        this.socialsecuritynumber = socialsecuritynumber;
        this.street1 = street1;
        this.street2 = street2;
        this.city = city;
        this.state = state;
        this.zip = zip;
        this.phone = phone;
        this.email = email;
    }
}

visitorrepository.java

@Repository
public interface visitorrepository extends CrudRepository<newvisitor, Long> {
}

我们的想法是捕获所有内容，从 MySQL 数据库未连接、无效数据输入、重复记录，基本上是任何阻止初始查询 visitorrepository.save(newvisitor) 工作的内容，并将其作为 JSON 返回到 Angular。我觉得 ResponseEntity 或 RestControllerAdvice 可能是答案，只是不确定是否是准确的最佳实施方式。

Answer 1

你已经有了答案。

我觉得 ResponseEntity 或 RestControllerAdvice 可能是答案

您只能使用您的格式创建一个 dto 响应。然后把它放在 ResponseEntity 中以防出错。