如何删除具有特定列号和行号的所有值？

Question

这段代码耗时太长：

List<DataLogg> selectedLogger = dataLoggRepository.findByLoggerId(loggerId.getValue());
for(int i = firstIndex-1; i < lastIndex; i++) {
    try {
        DataLogg dataLogg = selectedLogger.get(i);
        if (dataLogg != null) {
            dataLoggRepository.delete(dataLogg);
        }
    } catch(Exception e1) {}
}

有什么办法可以避免这个for循环，并且仍然删除firstIndex-1和lastIndex之间具有loggerId.getValue()列值的所有内容？

来自以下cmets的建议：

List<DataLogg> selectedLogger = dataLoggRepository.findByLoggerId(loggerId.getValue());
List<DataLogg> deleteThese = new ArrayList<DataLogg>();
for(int i = firstIndex-1; i < lastIndex; i++) {
    try {
        DataLogg dataLogg = selectedLogger.get(i);
        deleteThese.add(dataLogg);
    } catch(Exception e1) {}
}
dataLoggRepository.deleteInBatch(deleteThese);

Answer 1

使用java流API

selectedLogger
.stream()
.skip(firstIndex-2)
.limit(lastIndex-firstIndex+1)
.filter(loggerId.getValue()!=null)
.map(()->{dataLoggRepository.delete(dataLogg);});

Answer 2

    @Query(value = "Delete from dataLoggTable where dataLoggTable.id in " +
            "(select id from dataLoggTable offset :firstIndex)", 
            nativeQuery = true)
    @Modifying
    @Transactional
    void delete(int firstIndex);

Answer 3

只是另一种写法。

List<DataLogg> selectedLogger = dataLoggRepository.findByLoggerId(loggerId.getValue());
List<DataLogg> deleteThese = IntStream.range(firstIndex - 1, lastIndex).mapToObj(i -> selectedLogger.get(i)).collect(Collectors.toList());
dataLoggRepository.deleteInBatch(deleteThese);