【问题标题】:Getting null in mapping column in Hibernate bidirectional ManytoOne , OnetoMany在 Hibernate 双向 ManytoOne、OnetoMany 的映射列中获取 null
【发布时间】:2019-05-22 21:54:03
【问题描述】:

我正在尝试创建双向 OnetoMany、ManytoOne 映射。下面是实体类 StudentAddress 和 Student3 类:

Student3实体类:

@Entity
@Table(name="Student3", schema="cf_2583f365_c3c6_499a_a60d_138e7e7023eb")
public class Student3 {
@Id
@Column(name = "STUDENT_ID")
@GeneratedValue(strategy=GenerationType.IDENTITY)
private int student_id;

@Column(name = "STUDENT_NAME")
private String student_name;

@ManyToOne(cascade=CascadeType.ALL)
@JoinColumn(name="student_address_id",referencedColumnName="address_id")
/*@JoinColumn(name = "student_address_id")*/
private StudentAddress studentAddress;


@Override
public String toString() {
    return "Student3 [student_id=" + student_id + ", STUDENT_NAME=" + student_name + "]";
}

public int getStudent_id() {
    return student_id;
}

public void setStudent_id(int student_id) {
    this.student_id = student_id;
}

public String getStudent_name() {
    return student_name;
}

public void setStudent_name(String student_name) {
    this.student_name = student_name;
}

public StudentAddress getStudentAddress() {
    return studentAddress;
}

public void setStudentAddress(StudentAddress studentAddress) {
    this.studentAddress = studentAddress;
}

public Student3() {

}

}

学生地址实体类:

@Entity
@Table(name="StudentAddress", schema="cf_2583f365_c3c6_499a_a60d_138e7e7023eb")
public class StudentAddress {

@Id
@Column(name = "address_id")
@GeneratedValue(strategy=GenerationType.IDENTITY)
private int address_id;

@Column(name = "address_detail")
private String address_detail;

@OneToMany(cascade=CascadeType.ALL,mappedBy = "studentAddress")
private List<Student3> students;



@Override
public String toString() {
    return "StudentAddress [address_id=" + address_id + ", address_detail=" + address_detail + ", students="
            + students + "]";
}

public int getAddress_id() {
    return address_id;
}

public void setAddress_id(int address_id) {
    this.address_id = address_id;
}

public String getAddress_detail() {
    return address_detail;
}

public void setAddress_detail(String address_detail) {
    this.address_detail = address_detail;
}

public List<Student3> getStudents() {
    return students;
}

public void setStudents(List<Student3> students) {
    this.students = students;
}


public StudentAddress() {

}

}

在保存 Student3 对象的数据时,我可以像这样保存数据:

但是当我从 StudentAddress 端保存数据时,我在 student_address_id 列中得到一个空值:

从 Student3,studentAddress 端保存数据的代码:

/**************SAVE STUDENT Address Controller*************************/
@RequestMapping(value="/saveStudentAddress", method=RequestMethod.POST,consumes=MediaType.APPLICATION_JSON_VALUE)
public String savestudentaddress (@RequestBody StudentAddress s1) {

    System.out.println(s1);
    studentaddressRepository.save(s1);
    return "success";
}

/**************SAVE STUDENT3 Controller*************************/
@RequestMapping(value="/saveStudent3", method=RequestMethod.POST,consumes=MediaType.APPLICATION_JSON_VALUE)
public String savestudent (@RequestBody Student3 s1) {

    System.out.println(s1);
    student3Repository.save(s1);
    return "success";
}

从 Student3 端保存数据的 JSON:

{
    "student_id" :123, 
    "student_name": "avijit kumar Mamod",

    "studentAddress":{
                    "address_id" : 123,
                    "address_detail" : "209 - Berlington Street"
                    }           
}

从 StudentAddress 端保存数据的 Json:

{
"address_id" : 123,
"address_detail" : "209 - Berlington Street",
"students": [{
            "student_id" :123, 
            "student_name": "avijit kumar Mamod"
           }]
}

【问题讨论】:

  • 您能否展示一下您如何从 StudentAddress 端保存数据的代码?
  • @Abhi 我已经更新了我的 qn ,添加了相同的代码。

标签: java hibernate spring-boot hibernate-mapping


【解决方案1】:

今天,从StudentAddress 一侧删除mappedBy 并放入@JoinColumn(name="student_address_id"),当我尝试从studentAddress 一侧保存时,它确实在DB student_address_id 中增加了价值。

studentAddress 现在看起来像这样:

@OneToMany(cascade=CascadeType.ALL/*,mappedBy = "studentAddress"*/)
@JoinColumn(name="student_address_id")
private List<Student3> students;

我不知道为什么会这样。我没有上面答案中abhi建议的额外代码。控制器现在很简单:

@RequestMapping(value="/saveStudentAddress", method=RequestMethod.POST,consumes=MediaType.APPLICATION_JSON_VALUE)
public String savestudentaddress (@RequestBody StudentAddress s1) {
    System.out.println(s1);
   studentaddressRepository.save(s1);
    return "success";
}

【讨论】:

    【解决方案2】:

    修改您的 saveStudentAddress 代码,如下所示并尝试

    @RequestMapping(value="/saveStudentAddress", method=RequestMethod.POST,consumes=MediaType.APPLICATION_JSON_VALUE)
    public String savestudentaddress (@RequestBody StudentAddress s1) {
        System.out.println(s1);
    
        for(Student s: s1.getStudents()){
          s.setAddress(s1);
        }
    
        studentaddressRepository.save(s1);
        return "success";
    }
    

    【讨论】:

    • 它的工作!但我不明白,我们甚至没有保存's',我们还在保存's1'。为什么设置 s, wud 会有这么大的不同??
    • 这就是 Hibernate 文档在这种情况下建议保存对象的方式。希望它有所帮助。
    • 请看下面我的回答,这更离奇
    【解决方案3】:

    不要在两个类中都写 OneToMany。

    【讨论】:

    • 我已经编辑了我的问题,我错误地添加了 StudentAddress 类两次。现在Student3课已经上线了。
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