【发布时间】:2014-11-19 07:23:53
【问题描述】:
我正在努力访问下面的这个 json 代码。我之前看到的每个 json 值都是这样的:
var hold = { name: 'alex', job: 'realtor'}
所以要访问这个名字,我会做一些类似于 hold.name 的操作。但是我的json数据是这样的
[
[
{
"count": "80",
"countTxt":"Buyer logins",
"participantsTxt":"Total for all participating member companies:",
"participantCount":"523"
},
{
"count": "233",
"countTxt":"Searches",
"participantsTxt":"Total for all participating member companies:",
"participantCount":"628"
},
{
"count": "533",
"countTxt":"Views of our member pages",
"participantsTxt":"Total for all participating member companies:",
"participantCount":"2,365"
}
],
[
{
"count": "80",
"countTxt":"Total vists",
"participantsTxt":"Total for all participating member companies:",
"participantCount":"412"
},
{
"count": "53",
"countTxt":"Unique visitors",
"participantsTxt":"Total for all participating member companies:",
"participantCount":"731"
},
{
"count": "1:12 min",
"countTxt":"Total time spent on page",
"participantsTxt":"Total for all participating member companies:",
"participantCount":"784.2 mins"
}
]
]
数据是嵌套的,没有名称,所以我不知道如何访问。我知道这个问题似乎有些初级,但我还没有看到任何示例解析看起来像这样的代码。它总是像上面的一个更简单的例子。我的 .getjson 代码看起来像这样...
var requestURL = 'assets/js/stats.json';
$.getJSON(requestURL, function(data){
$.each(data, function(key, value) {
$('body').append($('<div>' + data[0].name, {
}));
console.log(data);
});
});
我的控制台返回两个像这样的对象
Array[3], Array[3]] Array[3]:
Array[3] [Array[3], Array[3]]
所以我知道它正在取回数据,我只需要能够选择我想要的内容并将其附加到 DOM。我尝试了十种不同的变体,但没有任何效果。请帮忙!?
【问题讨论】:
-
只需使用 [0] 访问第一个数组等。或者先遍历它们并使用索引访问它们
-
只使用 [0] 不起作用。这也是在 jsonlint.com 检查的有效 json