【发布时间】:2026-01-15 22:05:01
【问题描述】:
我正在尝试制作一个弹出窗口,如果用户点击取消,它将阻止用户转到结果页面。此代码适用于 Chrome、Safari、Opera、Microsoft Edge 和 Internet Explorer 11,但不适用于 Firefox。
function leavingAlert(){
var check = confirm("You are about to leave the site! You may be going to a website that doesn't provide security. Do you wish to continue?");
if(check){
this.target="_blank"
return true;
}else{
event.cancelBubble = true;
return false;
}
}
//WORKING FOR ALL NON-IFRAME LINKS
var container = document.getElementById("wrapper");
var allATags = wrapper.getElementsByTagName("A");
for(var i = 0, len = allATags.length; i < len; i++){
var link = allATags[i];
//var pat = /^https?:\/\//i;
var pat = new RegExp("https://example.com");
var pat2 = new RegExp("javascript");
if(!pat.test(link.href)){
if(!pat2.test(link.href)){
link.onclick = leavingAlert;
}
}
}
我也使用了这些而不是 event.cancelBubble,但没有运气:
event.preventDefault ? event.preventDefault() : event.returnValue = false;
和
event.stopImmediatePropagation;
和
event.stopPropagation;
在我实现此代码的地方,我目前无法使用 jQuery,因此最好使用纯 Javascript 的答案,谢谢!
【问题讨论】:
标签: javascript firefox preventdefault stoppropagation