【发布时间】:2017-08-21 18:40:19
【问题描述】:
我面临两个问题 1.我没有得到正确的HTML结构见下图
我要找的html结构:
- 如何为动态 JSON 编写代码,例如,我的 JSON 可能有 4 级子菜单,但我无法编写那么多循环和条件,因此尝试通过编写嵌套循环从 json 渲染李>
这是我尝试过的代码:
$(document).ready(function(){
var treeJson = {"values":[
{
"tree_title":"FashionWorld1",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{
"tree_title":"SubmenuLevel11",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{"tree_title":"SubmenuLevel21"},
{"tree_title":"SubmenuLevel22"},
{"tree_title":"SubmenuLevel23"}
]
}
]
},
{"tree_title":"SubmenuLevel12"},
{"tree_title":"SubmenuLevel13"}
]
}
]
},
{
"tree_title":"FashionWorld2",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{
"tree_title":"SubmenuLevel11",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{"tree_title":"SubmenuLevel21"},
{"tree_title":"SubmenuLevel22"},
{"tree_title":"SubmenuLevel23"}
]
}
]
},
{"tree_title":"SubmenuLevel12"},
{"tree_title":"SubmenuLevel13"}
]
}
]
},
{
"tree_title":"FashionWorld3",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{
"tree_title":"SubmenuLevel11",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{"tree_title":"SubmenuLevel21"},
{"tree_title":"SubmenuLevel22"},
{"tree_title":"SubmenuLevel23"}
]
}
]
},
{"tree_title":"SubmenuLevel12"},
{"tree_title":"SubmenuLevel13"}
]
}
]
},
{
"tree_title":"FashionWorld4",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{
"tree_title":"SubmenuLevel11",
"tree_image":"img_arrow",
"tree_image_position":"1",
"tree_image":"FashionWorld",
"isopen":"0",
"child":[
{
"values":[
{"tree_title":"SubmenuLevel21"},
{"tree_title":"SubmenuLevel22"},
{"tree_title":"SubmenuLevel23"}
]
}
]
},
{"tree_title":"SubmenuLevel12"},
{"tree_title":"SubmenuLevel13"}
]
}
]
}
]};
var treeParentArr = treeJson.values;
if(treeParentArr.length){
var $ulLevel1 = $("<ul />").appendTo($("#tree"));
//level 1
for (var i = 0; i < treeParentArr.length; i++) {
var treeParentVal = treeParentArr[i];
var listChildLevel1 = $ulLevel1.append($("<li />", { text: treeParentVal.tree_title }));
var childSubVal1 = treeParentVal.child;
if(childSubVal1){
var treechildLevel1 = childSubVal1[0].values;
//level 2
//check the condition data is there or not
if(treechildLevel1.length){
console.log(i);
var $ulLevel2 = $("<ul />").appendTo($(listChildLevel1));
for (var j = 0; j < treechildLevel1.length; j++) {
var treeChildLevelData1 = treechildLevel1[j];
var listChildLevel2 = $ulLevel2.append($("<li />", { text: treeChildLevelData1.tree_title }));
//level 3
//check the condition data is there or not
var childSubVal2 = treeChildLevelData1.child;
if(childSubVal2){
var treechildLevel2 = childSubVal2[0].values;
if(treechildLevel2.length){
//console.log(treechildLevel2);
var $ulLevel3 = $("<ul />").appendTo($(listChildLevel2));
for (var k = 0; k < treechildLevel2.length; k++) {
var treeChildLevelData2 = treechildLevel2[k];
$ulLevel3.append($("<li />", { text: treeChildLevelData2.tree_title }));
}
}
}
}
}
}
}
}
});
JSFiddle
【问题讨论】:
标签: javascript jquery html css json