如果在codeigniter中验证失败，我如何保持变量值

Question

我想验证一个表单，以确保在这种情况下用户在描述字段中输入的内容是正确的。

但是，

在这里，我通过从 function 1

获取值来将值传递给 function 2

函数 2 首次加载时，它会获取数据并显示值（OK）

但是当函数 2 重新提交验证和提交数据时，这些 valitable 会变为空并抛出错误 Message: Undefined variable: query (ERROR)

我不知道该怎么做，呵呵。我只是一个新手 PHP 程序员。

这是我目前所拥有的：

功能1

public function ask()
{
$this->load->model('MainM');
$this->load->library('form_validation');
$this->form_validation->set_rules('index', 'AL Index', 'trim|required|min_length[7]|max_length[7]');
if($this->form_validation->run() == FALSE) {
        $this->load->view('enterindex');
    }else{
        $query = null; //emptying in case 
        $index = $this->input->post("index"); //getting from post value
        $query = $this->db->get_where('tbl_reg', array('reg_index' => $index));         
        $count = $query->num_rows(); //counting result from query           
        if ($count == 1) {
        $data['query'] = $this->MainM->getregdata($index);  
        $result = $this->load->view('submitques',$data);
    }else{
        $data = array();
        $data['error'] = 'error';
        $this->load->view('enterindex', $data);
    }   
}

功能2

public function submitq()
{
$this->load->library('form_validation');
$this->form_validation->set_rules('yourq', 'Question', 'required|min_length[7]'); 
    if($this->form_validation->run() == FALSE) {            
        $this->load->view('submitques',$data);
    } else {        
     //insert the submitq form data into database
        $data = array(
            'reg_id' => $this->input->post('reg_id'),
            'ques' => $this->input->post('yourq'),
            'call' => "yes",
            'status' => "New",
            'date' => date('Y-m-d H:i:s')
        );
            if ($this->db->insert('tbl_ques', $data))                   
        {
            // success
           $this->session->set_flashdata('success_msg', 'Your Submission is success');
           redirect('main/submitq');
        }
        else
        {
            $this->load->view('submitques', $data);
        }     
    }   

}

Answer 1

实际上你有 $data 变量放在 else 部分所以这就是为什么出现这个错误你需要在循环之前定义。

public function submitq()
{
    $this->load->library('form_validation');
    $this->form_validation->set_rules('yourq', 'Question', 'required|min_length[7]'); 
// define here before check condtions
    $data = array(
        'reg_id' => $this->input->post('reg_id'),
        'ques' => $this->input->post('yourq'),
        'call' => "yes",
        'status' => "New",
        'date' => date('Y-m-d H:i:s')
    );
    if($this->form_validation->run() == FALSE) {            
        $this->load->view('submitques',$data);
    } else {        
        //insert the submitq form data into database
            if ($this->db->insert('tbl_ques', $data))                   
        {
            // success
            $this->session->set_flashdata('success_msg', 'Your Submission is success');
            redirect('main/submitq');
        }
        else
        {
            $this->load->view('submitques', $data);
        }     
    }   

}

Answer 2

如果您希望在false 条件下使用已发布的$data 变量，您可以将其移到验证块之外：

public function submitq()
{
    $this->load->library('form_validation');
    $this->form_validation->set_rules('yourq', 'Question', 'required|min_length[7]'); 
    $data = array(
        'reg_id' => $this->input->post('reg_id'),
        'ques' => $this->input->post('yourq'),
        'call' => "yes",
        'status' => "New",
        'date' => date('Y-m-d H:i:s')
    );
    if($this->form_validation->run() == FALSE) {            
        $this->load->view('submitques',$data);
    } else {        
        //insert the submitq form data into database
            if ($this->db->insert('tbl_ques', $data))                   
        {
            // success
            $this->session->set_flashdata('success_msg', 'Your Submission is success');
            redirect('main/submitq');
        }
        else
        {
            $this->load->view('submitques', $data);
        }     
    }   

}

Answer 3

试试这个代码：

首先将表单库添加到config/autoload.php

$autoload['libraries'] = array('database','form_validation');

html代码

这是查看文件login.php

  <?php echo form_open('action_controller_name', array('class' => '', 'enctype' => 'multipart/form-data', 'role' => 'form', 'name' => 'myform', 'id' => 'myform')); ?>
  <div class="form-group">
      <label class="control-label" for="mobile">Mobile-No</label>
      <input type="text" name="mobile" value="" placeholder="Enter Mobile No" id="mobile" class="form-control" /> 
      <label class="error"><?php echo form_error('mobile'); ?></label>
  </div>
  <div class="form-group">
      <label class="control-label" for="password">Password</label>
      <input type="password" name="password" value="" placeholder="Password" id="password" class="form-control" /> 
      <label class="error"><?php echo form_error('mobile'); ?></label>
  </div>
  <input type="submit" value="Login" class="btn btn-gray" id="submit" /> 
  <a class="forgotten" href="<?php echo base_url('login/forgot_password'); ?>" style="font-size: 13px;">Forgot Password</a> 
  <?php
  echo form_close();
  ?>

我的动作控制器

public function action_controller_name() {
        $this->load->helper(array('form'));  // Load Form Library
        $this->load->library('form_validation'); // Load Form Validaton Library
        $this->form_validation->set_rules('mobile', 'mobile', 'required', array('required' => 'Please Enter Mobile Number.'));
        $this->form_validation->set_rules('password', 'Password', 'required', array('required' => 'Please Enter passsword.'));
        if ($this->form_validation->run() === TRUE) {  // Check validation Run
            // Your Login code write here
        } else {
            $this->load->view('login', $this->data);
        }
    }

试试这个代码。如果codeigniter验证失败，你可以保留变量值。