【问题标题】:Hibernate Mapping Exception : Repeated column in mapping for entity休眠映射异常:实体映射中的重复列
【发布时间】:2012-03-11 23:14:16
【问题描述】:

特定实体存在映射异常。 无法弄清楚问题出在哪里。 我从头到尾检查了所有映射 3 次。 我仍然得到一个映射异常。

发给员工的电子邮件只映射一次。 但是还是报错repeated mapping

错误是:

Caused by: org.hibernate.MappingException: Repeated column in mapping for entity: com.cluster.entity.Email column: EMPLOYEE_ID (should be mapped with insert="false" update="false")
    at org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:680)
    at org.hibernate.mapping.PersistentClass.checkPropertyColumnDuplication(PersistentClass.java:702)
    at org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:724)
    at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:477)
    at org.hibernate.mapping.RootClass.validate(RootClass.java:268)
    at org.hibernate.cfg.Configuration.validate(Configuration.java:1287)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1729)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1775)
    at com.cluster.util.HibernateUtil.<clinit>(HibernateUtil.java:16)
    ... 1 more

给 Pojo 发电子邮件

package com.cluster.entity;

public class Email {

    private int intEmailID;
    private String strEmailName;

    //many to one
    private EmailType emailType;

    //many to one
    private Employee employee;

    public int getIntEmailID() {
        return intEmailID;
    }

    public void setIntEmailID(int intEmailID) {
        this.intEmailID = intEmailID;
    }

    public String getStrEmailName() {
        return strEmailName;
    }

    public void setStrEmailName(String strEmailName) {
        this.strEmailName = strEmailName;
    }

    public EmailType getEmailType() {
        return emailType;
    }

    public void setEmailType(EmailType emailType) {
        this.emailType = emailType;
    }

    public Employee getEmployee() {
        return employee;
    }

    public void setEmployee(Employee employee) {
        this.employee = employee;
    }

}

email.hbm.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC
        '-//Hibernate/Hibernate Mapping DTD 3.0//EN'
        'http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd'>


<hibernate-mapping package="com.cluster.entity" >
    <class name="Email" table="EMAIL">

        <id name="intEmailID" column="EMAIL_ID"> 
            <generator class="sequence">
                <param name="sequence">EMAIL_ID_SEQ</param>
            </generator>
        </id>

        <property name="strEmailName" column = "EMAIL_NAME"/>

        <many-to-one name="employee" column="EMPLOYEE_ID" not-null = "true" class = "Employee"/>

        <many-to-one name="emailType" column="EMAIL_TYPE_ID" not-null = "true" class = "EmailType"/>

    </class>

</hibernate-mapping>

相关脚本

CREATE TABLE EMPLOYEE
(
  EMPLOYEE_ID      NUMBER                       NOT NULL,
  FIRSTNAME        VARCHAR2(20 BYTE)            NOT NULL,
  LASTNAME         VARCHAR2(20 BYTE)            NOT NULL,
  DATE_OF_BIRTH    VARCHAR2(20 BYTE)            NOT NULL,
  SALARY           VARCHAR2(10 BYTE)            NOT NULL,
  DEPARTMENT_ID    NUMBER                       NOT NULL
);


CREATE TABLE EMAIL
(
 EMAIL_ID              NUMBER              NOT NULL,
 EMAIL_NAME            VARCHAR2(40 BYTE)   NOT NULL,
 EMPLOYEE_ID           NUMBER              NOT NULL,
 EMAIL_TYPE_ID         NUMBER              NOT NULL
);


CREATE TABLE EMAIL_TYPE
(
 EMAIL_TYPE_ID         NUMBER              NOT NULL,
 EMAIL_TYPE_NAME       VARCHAR2(40 BYTE)   NOT NULL
);


ALTER TABLE EMPLOYEE ADD 
(
 CONSTRAINT PK_EMPLOYEE_ID
 PRIMARY KEY (EMPLOYEE_ID)
);

ALTER TABLE EMAIL_TYPE ADD 
(
 CONSTRAINT PK_EMAIL_TYPE_ID
 PRIMARY KEY (EMAIL_TYPE_ID)
);

ALTER TABLE EMAIL ADD
(
 CONSTRAINT PK_EMAIL_ID
 PRIMARY KEY (EMAIL_ID)
);

ALTER TABLE EMAIL ADD
( 
 CONSTRAINT FK_EMAIL_EMPLOYEE_ID
 FOREIGN KEY (EMPLOYEE_ID)
 REFERENCES EMPLOYEE (EMPLOYEE_ID)
);

ALTER TABLE EMAIL ADD
( 
 CONSTRAINT FK_EMAIL_EMAIL_TYPE_ID
 FOREIGN KEY (EMAIL_TYPE_ID)
 REFERENCES EMAIL_TYPE (EMAIL_TYPE_ID)
);

发给员工的电子邮件只映射一次。 但是还是报错repeated mapping

【问题讨论】:

    标签: hibernate jakarta-ee orm persistence hibernate-mapping


    【解决方案1】:

    您是否将 Employee 中的集合设置为反向?

    <bag name="emails" inverse="true">
      <key column="EMPLOYEE_ID" not-null="true">
      ...
    </bag>
    

    【讨论】:

    • inverse 表示 Child (Email) 负责关联。所以孩子是EMPLOYEE_ID 的所有者,必须插入/更新它。父级仅使用该字段来了解其子级,但不插入/更新它
    • 同样,我在双向关系的两边都有@JoinColumn。然而,这个模棱两可的错误信息让我陷入了一场刚刚结束的疯狂追逐。
    【解决方案2】:

    对于那些使用注解来解决这个问题的人来说,类应该是这样的:

    @Entity
    public class Email {
    
        @Id
        @GeneratedValue(strategy=GenerationType.SEQUENCE)
        private int intEmailID;
    
        @Column(insertable = false, updatable = false)
        private int employeeId;
    
        @ManyToOne
        private EmailType emailType;
    
        @ManyToOne
        @JoinColumn(name="employeeId")
        private Employee employee;
    
        // Getters and Setter
    }
    
    
    @Entity
    public class Employee {
    
        @Id
        private int id;
    
        @OneToMany(cascade = {CascadeType.ALL}, mappedBy="employeeId")
        @PrimaryKeyJoinColumn
        private List<Email> emailList;
    
        public void setEmailList(List<Email> emailList) {
            this.emailList = emailList
        }
    
        public List<Email> getEmailList() {
            return emailList;
        }
    
        // Rest of getters and setters
    
    }
    

    【讨论】:

      【解决方案3】:

      我认为您已使用 oneToMany 关系将 Employee 映射到 Email。如果是,则没有错,但您必须确保只能在一个方向插入和更新

      应该在Employee中用insert="false" update="false"映射

      【讨论】:

      • 是的......你是对的!我试过了.. 我们要么做 inverse = "true",要么照你说的做!
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