【发布时间】:2018-05-04 20:42:08
【问题描述】:
我对 java 编程比较陌生。我目前正在构建一个迷你猜谜游戏,作为一个学习更多 Java 的项目。我遇到以下问题:
以下是我无法解决的 4 个主要问题。
- 记录每个用户的答案,如果不正确。
- 如果用户正确,则在后续回合中跳过它们。
- 一旦所有玩家都猜对了他们的数字,打印出每个人猜对的次数、不正确的答案,并显示玩家的排名。
- 询问用户是否希望再次播放。如果是这样,请重置所有值。
这是我写的方法;
import java.io.*;
public class MultiPlayerRandomGame {
// this method asks how many users will be playing and returns the number of users
public static int howManyUsers() {
System.out.println("How many users will be playing?");
int players = IO.readInt();
return players;
}
// this method generates and returns a random number
public static int generateRandomNumber() {
int randomNumber = (int) (Math.random() * 100);
return randomNumber;
}
// this method compares user's entered guess and the generated random number then returns true/false
public static boolean compareGuess(int guess, int randomNumbers) {
boolean isGuessCorrect = false;
if (guess == randomNumbers) {
System.out.println("CORRECT!");
isGuessCorrect = true;
} else if (guess > randomNumbers) {
System.out.println("Too High");
} else if (guess < randomNumbers) {
System.out.println("Too Low");
}
System.out.println("test1");
return isGuessCorrect;
}
// this method determines whether Player N is correct or incorrect
public static boolean nextPlayer(int numOfUsers, int[] numberOfGuesses, int[] randomNumbers, int[][] numberBoard) {
for (int n = 0; n < numOfUsers; n++) {
int guessedNumber = numberOfGuesses[n];
/* if (guessedNumber == 0) {
return false;
}*/
if (numberBoard[n][guessedNumber] != randomNumbers[n]) {
return false;
}
}
return true;
}
/* this method is supposed to print out the number of guesses it took each player to guess their correct number
* CORRECTION: change the logic of this method to printing the number of guesses for one player then
* in the main method or wherever, make a for loop that prints out the number of guesses for each player
*/
public static void amountOfGuesses(int numOfUsers, int [] numberOfGuesses, int [][] numberBoard) {
int n = 0;
for ( int i = 0; i < numOfUsers; i++ ) {
n = n + 1;
System.out.println("Player " + n + " guessed " + numberOfGuesses[i]+ " time(s)");
}
}
// this method determines whether the user(s) would like to play again
public static boolean playAgain(String answer) {
boolean userWillPlayAgain;
if (answer.compareToIgnoreCase("no") == 0) {
userWillPlayAgain = false;
}
else {
userWillPlayAgain = true;
}
return userWillPlayAgain;
}
// this method controls the entire game
public static boolean playGame(){
boolean gameTerminate = false;
int numOfUsers = howManyUsers();
int [] randomNumbers = new int[numOfUsers];
int [] numberOfGuesses = new int [numOfUsers];
int [][] numberBoard = new int [numOfUsers][100];
// this for loop assigns the n random number(s) to the n player(s)
for (int n = 0; n < numOfUsers; n++){
randomNumbers[n] = generateRandomNumber();
System.out.println("PLAYER " + (n+1) + "'s RANDOM NUMBER: " + randomNumbers[n]);
}
do {
for (int i = 0; i < numOfUsers; i++) {
int guessedNumber = numberOfGuesses[i];
if (guessedNumber == 0 || numberBoard[i][guessedNumber-1] != randomNumbers[i]) {
System.out.println("Enter your guess Player " + (i+1) + ":");
int enteredGuess = IO.readInt();
numberBoard[i][guessedNumber] = enteredGuess;
numberOfGuesses[i] = guessedNumber + 1;
if(compareGuess(enteredGuess, randomNumbers[i])){
return true;
}
}
}
/* int n = 0;
* for ( int j = 0; j < numOfUsers; j++ ) {
n = n + 1;
System.out.println("Player " + n + " guessed " + numberOfGuesses[j]+ " time(s)"); }
*/
} while (nextPlayer(numOfUsers, numberOfGuesses, randomNumbers, numberBoard) == false);
// System.out.println("test");
return gameTerminate;
}
public static void main(String[] args){
boolean playing = true;
while (playing) {
playGame();
System.out.println("Would you like to play again?");
String answer = IO.readString();
playing = playAgain(answer);
}
System.out.println("OK, goodbye!");
}
}
目前的主要问题:游戏终止并在玩家猜到他们的号码后询问用户是否想再次玩,而不是在每个玩家都猜到他们的号码后。
我是否需要实际的对象来实现这一点并跟踪每个玩家,还是在没有对象的情况下仍然可以解决这个问题?这是我不熟悉的领域。
【问题讨论】: