如何检查两个查询是否成功执行？

Question

我想插入 2 个不同的表。人们将填写一份表格，在其中输入他们的用户数据和公司数据。我测试了这个表格，当一切都正确时它很好，但是......当用户数据正常并且公司数据有错误时，用户插入运行并且我不想要它。反之亦然。。 我现在的代码：（只是一个标记）

$sql = "INSERT INTO user (name, email, password) VALUES (:username, :email, :password)";
  $stmt = $dbh->prepare($sql) {
    ... //bind parameters
    if($stmt->execute()){
      echo "Successfully registered user";
    $sql = "INSERT INTO company (title, number, address) VALUES (:title, :number, :address)";
      $stmt = $dbh->prepare($sql) {
        ... //bind parameters
        if($stmt->execute()){
        echo "Successfully registered company";
      }
    }
  }
}
unset($stmt);

我想检查两个，当没有错误时，然后运行两个查询。 如何嵌套？

Answer 1

您可以将事务beginTransaction、rollBack、commit 与try and catch 一起使用。

$dbh->beginTransaction()
try {
$sql = "INSERT INTO user (name, email, password) VALUES (:username, :email, :password)";
  $stmt = $dbh->prepare($sql) {
    ... //bind parameters
    if($stmt->execute()){
      echo "Successfully registered user";
    $sql = "INSERT INTO company (title, number, address) VALUES (:title, :number, :address)";
      $stmt = $dbh->prepare($sql) {
        ... //bind parameters
        if($stmt->execute()){
        echo "Successfully registered company";
      }
    }
  }
}
} catch(\Exception $e) 
    $dbh->rollBack();
}
$dbh->commit();
unset($stmt);

Answer 2

    try {
        $pdo->prepare($agr_query_string);
        $commited = $pdo->commit();
        if($commited){
         echo "Success";
        }else{
         echo "Fail";
         $pdo->rollBack();
        }
      } catch (PDOException $e) {

        $pdo->rollBack();
        print "rollBack : fail";

        //throw new $e;
    }