【问题标题】:Cannot deserialize instance of object out of START_ARRAY token in Spring Webservice无法从 Spring Webservice 中的 START_ARRAY 令牌反序列化对象实例
【发布时间】:2014-10-20 00:43:51
【问题描述】:

我目前无法连接到我在 android 上的网络服务。我使用 jackson-core/databind/annotation-2.2.4 和 Spring RESTWebService。如果我从浏览器访问 URL,我可以看到 JSON 响应:(服务器返回 List\Shop\ 看起来像:)

[{"name":"shopqwe","mobiles":[],"address":{"town":"city",
"street":"streetqwe","streetNumber":"59","cordX":2.229997,"cordY":1.002539},
"shoe" [{"shoeName":"addidas","number":"631744030","producent":"nike","price":999.0,
"sizes":[30.0,35.0,38.0]}]

从客户端端点(Android 应用程序)我收到以下错误消息:

08-26 17:43:07.406: E/AllShopsAsyc(28203): Could not read JSON: Can not deserialize
instance of com.auginzynier.data.ShopContainer out of START_ARRAY token
08-26 17:43:07.406: E/AllShopsAsyc(28203):  at [Source:
com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1,
column: 1]; nested exception is com.fasterxml.jackson.databind.JsonMappingException:
Can not deserialize instance of com.auginzynier.data.ShopContainer out of START_ARRAY
token
08-26 17:43:07.406: E/AllShopsAsyc(28203):  at [Source:
com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1,
column: 1] 
08-26 17:43:07.406: E/AllShopsAsyc(28203):
org.springframework.http.converter.HttpMessageNotReadableException: Could not read
JSON: Can not deserialize instance of com.auginzynier.data.ShopContainer out of
START_ARRAY token

我的服务器请求

RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
ShopContainer response  = restTemplate.getForObject(url, ShopContainer.class);

ShopContainer 在哪里:

public class ShopContainer {
   private List<Shop> shops;

Shop、Address 和 Shoe 的结构是:(我省略了 getter 和 setter):

public class Shop {
@JsonProperty("name")    private String name;
@JsonProperty("mobiles")   private List<String> mobiles = new ArrayList<String>();
@JsonProperty("address")   private Address address;
@JsonProperty("shoe") private List<Shoe> shoe = new ArrayList<Shoe>();

public class Address {
@JsonProperty("town") private String town;
@JsonProperty("street") private String street;
@JsonProperty("streetNumber") private String streetNumber;
@JsonProperty("cordX") private Double cordX;
@JsonProperty("cordY") private Double cordY;

public class Shoe {
@JsonProperty("shoeName") private String shoeName;
@JsonProperty("number") private String number;
@JsonProperty("producent") private String producent;
@JsonProperty("price") private Double price;
@JsonProperty("sizes") private List<Double> sizes = new ArrayList<Double>();

我在这里和谷歌上看过,但仍然无法弄清楚我现在缺少什么。

任何回应都会非常有帮助。

问候。

@UPDATE

我已经通过使用杰克逊的 ObjectMapper 和 RequestMethod.GET 修复了 JSON。它现在返回一个字符串。

list is List<Shop>

ObjectMapper mapper = new ObjectMapper();
mapper.writeValue(new File("D:\\Android\\shop.json"), list);
System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list));
return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list);

控制台中的 JSON 如下所示:

[ {
  "name" : "shopqwe",
  "mobiles" : [ ],
  "address" : {
    "town" : "city",
    "street" : "streetqwe",
    "streetNumber" : "59",
    "cordX" : 2.229997,
    "cordY" : 2.002539
  },
  "shoe" : [ {
    "shoeName" : "addidas",
    "number" : "631744033",
    "producent" : "nike",
    "price" : 10.0,
    "sizes" : [ 30.0, 35.0, 38.0 ]
  } ]
} ]

请求仍然不起作用 - 错误是一样的。

【问题讨论】:

    标签: android json spring web-services jackson


    【解决方案1】:

    您的 json 包含一个数组,但您正试图将其解析为一个对象。 出现此错误是因为对象必须以 { 开头。

    你有两个选择:

    1. 您可以摆脱 ShopContainer 类并改用 Shop[]

      ShopContainer response  = restTemplate.getForObject(
          url, ShopContainer.class);
      

      替换为

      Shop[] response  = restTemplate.getForObject(url, Shop[].class);
      

      然后从中制作您想要的对象。

    2. 您可以更改服务器以返回对象而不是列表

      return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list);
      

      替换为

      return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(
          new ShopContainer(list));
      

    【讨论】:

    • 什么 id shop[] 是另一个对象的内部字段,而不是主对象。我们如何将其与父对象的映射分开?
    【解决方案2】:

    认为您发布的 JSON 实际上是您在浏览器中看到的内容,那么问题出在 JSON 本身。

    您发布的 JSON sn-p 格式不正确。

    您已发布:

    [{
            "name" : "shopqwe",
            "mobiles" : [],
            "address" : {
                "town" : "city",
                "street" : "streetqwe",
                "streetNumber" : "59",
                "cordX" : 2.229997,
                "cordY" : 1.002539
            },
            "shoe"[{
                    "shoeName" : "addidas",
                    "number" : "631744030",
                    "producent" : "nike",
                    "price" : 999.0,
                    "sizes" : [30.0, 35.0, 38.0]
                }]
    

    而正确的 JSON 应该是:

    [{
            "name" : "shopqwe",
            "mobiles" : [],
            "address" : {
                "town" : "city",
                "street" : "streetqwe",
                "streetNumber" : "59",
                "cordX" : 2.229997,
                "cordY" : 1.002539
            },
            "shoe" : [{
                    "shoeName" : "addidas",
                    "number" : "631744030",
                    "producent" : "nike",
                    "price" : 999.0,
                    "sizes" : [30.0, 35.0, 38.0]
                }
            ]
        }
    ]
    

    【讨论】:

    • 谢谢,我将 RequestMethod.GET 更改为返回包含 mapper.writeValue(new File("D:\\Android\\shop.json"), list); 的字符串;返回 mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list); 它返回正确的 JSON,但错误并没有消失
    • 尝试实现可序列化接口怎么样?
    【解决方案3】:

    我在使用spring-boot-starter-data-redis 时遇到了非常相似的问题。在我的实现中,为RedisTemplate 提供了一个@Bean,如下所示:

    @Bean
    public RedisTemplate<String, List<RoutePlantCache>> redisTemplate(RedisConnectionFactory connectionFactory) {
        final RedisTemplate<String, List<RoutePlantCache>> template = new RedisTemplate<>();
        template.setConnectionFactory(connectionFactory);
        template.setKeySerializer(new StringRedisSerializer());
        template.setValueSerializer(new Jackson2JsonRedisSerializer<>(RoutePlantCache.class));
    
        // Add some specific configuration here. Key serializers, etc.
        return template;
    }
    

    修复方法是指定RoutePlantCache 的数组,如下所示:

    template.setValueSerializer(new Jackson2JsonRedisSerializer<>(RoutePlantCache[].class));
    

    在我遇到的例外情况下:

    com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `[...].RoutePlantCache` out of START_ARRAY token
     at [Source: (byte[])"[{ ... },{ ... [truncated 1478 bytes]; line: 1, column: 1]
        at com.fasterxml.jackson.databind.exc.MismatchedInputException.from(MismatchedInputException.java:59) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.DeserializationContext.reportInputMismatch(DeserializationContext.java:1468) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.DeserializationContext.handleUnexpectedToken(DeserializationContext.java:1242) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.DeserializationContext.handleUnexpectedToken(DeserializationContext.java:1190) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.deser.BeanDeserializer._deserializeFromArray(BeanDeserializer.java:604) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.deser.BeanDeserializer._deserializeOther(BeanDeserializer.java:190) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:166) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:4526) ~[jackson-databind-2.11.4.jar:2.11.4]
        at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3572) ~[jackson-databind-2.11.4.jar:2.11.4]
    

    【讨论】:

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