使用if语句检查xml文件中是否存在数字？

Question

我有一个用户输入 6 个数字的表单，然后我使用 SimpleXML 将输入的数字与 xml 元素进行比较。如果找到正确的数字，则将其存储在变量（$n1 - $n6）中。这些变量在 foreach 循环之外用于确定是否所有 6 个数字都正确，然后回显元素的日期和累积奖金。这可以正常工作。

如果输入的数字与 xml 元素不匹配，我想回显一个不正确的结果（“抱歉”）。但是，这部分不起作用，因为它仍然回显日期和累积奖金，它没有链接 xml 中的数字。它会产生一个随机的日期和头奖号码，它们不会存储在 xml 文件中。

我如何确保输入 6 个错误数字时结果是错误的并回显“Sorry”？

XML：

<lottery>
<number>
  <date>7.11.2015</date>
  <num1>2</num1>
  <num2>3</num2>
  <num3>34</num3>
  <num4>43</num4>
  <num5>49</num5>
  <num6>50</num6>
  <jackpot>13156375</jackpot>
</number>
<number>
  <date>08.11.2015</date>
  <num1>11</num1>
  <num2>13</num2>
  <num3>18</num3>
  <num4>25</num4>
  <num5>29</num5>
  <num6>47</num6>
  <jackpot>8842605</jackpot>
</number>
</lottery>

PHP：

$n1 = false;//make true once we find 1st num
$n2 = false;//make true once we find 2nd num
$n3 = false;
$n4 = false;
$n5 = false;
$n6 = false;

$xml = simplexml_load_file('lottery2.xml') or die("Error: Cannot create object");
            if (isset($_POST['num1']) && isset($_POST['num2'])) {

            foreach ($xml->children() as $record) {
                $n1 = $n1 || $record -> num1 == $num1 || $record -> num2 == $num1 || $record -> num3 == $num1 || $record -> num4 == $num1 || $record -> num5 == $num1 || $record -> num6 == $num1;
                $n2 = $n2 || $record -> num1 == $num2 || $record -> num2 == $num2 || $record -> num3 == $num2 || $record -> num4 == $num2 || $record -> num5 == $num2 || $record -> num6 == $num2;
                $n3 = $n3 || $record -> num1 == $num3 || $record -> num2 == $num3 || $record -> num3 == $num3 || $record -> num4 == $num3 || $record -> num5 == $num3 || $record -> num6 == $num3;
                $n4 = $n4 || $record -> num1 == $num4 || $record -> num2 == $num4 || $record -> num3 == $num4 || $record -> num4 == $num4 || $record -> num5 == $num4 || $record -> num6 == $num4;
                $n5 = $n5 || $record -> num1 == $num5 || $record -> num2 == $num5 || $record -> num3 == $num5 || $record -> num4 == $num5 || $record -> num5 == $num5 || $record -> num6 == $num5;
                $n6 = $n6 || $record -> num1 == $num6 || $record -> num2 == $num6 || $record -> num3 == $num6 || $record -> num4 == $num6 || $record -> num5 == $num6 || $record -> num6 == $num6;

                    if ($n1 && $n2 && $n3 && $n4 && $n5 && $n6) break; //Found match. No need to keep looking

                }//end foreach

                if ($n1 && $n2 && $n3 && $n4 && $n5 && $n6) 
                {
                 echo $record -> date;
                 echo $record -> jackpot;
                }
                else
                {
                 echo "Sorry no winnings";
                }

Answer 1

如果您认为应该考虑使用数组而不是庞大的 if 语句。

我会这样做：

• 建立球员号码列表并排序
• 对于 XML 文件中的每个条目：
  • 建立彩票号码列表并对其进行排序
  • 使用排序后的数组将玩家号码与彩票号码进行比较

示例代码：

$xml = simplexml_load_file('lottery2.xml') or die("Error: Cannot create object");

if(isset($_POST['num1']) && isset($_POST['num2'])) {
  $myList = array($num1, $num2, $num3, $num4, $num5, $num6);
  $result = array();
  $win = 0;

  sort($myList);

  foreach ($xml->children() as $record) {
    for($n = 0; $n < 6; $n++) {
      $result[$n] = (int)$record -> {'num'.($n + 1)};
    }
    sort($result);

    if (match($myList, $result)) {
      echo $record -> date;
      echo $record -> jackpot;
      $win++;
    }
  }
  if($win == 0) {
    echo "Sorry no winnings";
  }
}

function match ($list1, $list2) {
  for($n = 0; $n < 6; $n++) {
    if($list1[$n] != $list2[$n]) {
      return false;
    }
  }
  return true;
}