【发布时间】：2017-03-18 23:47:48
【问题描述】：
我对 Android Studio 和 SQLiteDatabases 非常陌生。我需要以下帮助：
数据库，成功创建并可以显示值。但是，我正在尝试在创建时为每个患者创建一个自定义唯一 ID。 ID 应介于 000000-999999（6 位唯一 ID）之间。
应用的工作方式是：
1. User can "add patient"
2. User enters firstName and lastName
3. User than selects a department from a spinner
4. once the user has completed the above steps, he/she can click "Add Patient"
5. Then the values are displayed in a TabbedView, however the textView is horizontal rather than vertical.
6. and its displayed in a ListView
我已经能够完成上述所有步骤。我现在需要帮助来为患者创建一个唯一的 ID。任何帮助将不胜感激
请看下面的代码：
PatientDbHelper.java // Creates the tables and database
package tanav.sharma;
import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
import android.util.Log;
/**
* Created by Tanav on 11/4/2016.
*/
public class PatientDbHelper extends SQLiteOpenHelper {
private static final String DATABASE_NAME = "PATIENTINFO.db";
private static final int DATABASE_VERSION = 1;
private static final String CREATE_QUERY =
"CREATE TABLE "+PatientInfo.NewPatientInfo.TABLE_NAME+" ("+ PatientInfo.NewPatientInfo.PATIENT_FNAME+ " TEXT,"+PatientInfo.NewPatientInfo.PATIENT_LNAME+" TEXT,"+PatientInfo.NewPatientInfo.PATIENT_DEPARTMENT+" TEXT);";
public PatientDbHelper(Context context){
super(context,DATABASE_NAME,null,DATABASE_VERSION);
Log.e("DATABASE OPERATIONS","Database created / opened ...");
}
@Override
public void onCreate(SQLiteDatabase db) {
db.execSQL(CREATE_QUERY);
Log.e("DATABASE OPERATIONS","Table created...");
}
public void addInformations(String fname, String lname, String department, SQLiteDatabase db){
ContentValues contentValues = new ContentValues();
contentValues.put(PatientInfo.NewPatientInfo.PATIENT_FNAME,fname);
contentValues.put(PatientInfo.NewPatientInfo.PATIENT_LNAME,lname);
contentValues.put(PatientInfo.NewPatientInfo.PATIENT_DEPARTMENT,department);
db.insert(PatientInfo.NewPatientInfo.TABLE_NAME, null,contentValues);
Log.e("DATABASE OPERATIONS","One in row inserted...");
}
public Cursor getInformations(SQLiteDatabase db){
Cursor cursor;
String[] projections = {PatientInfo.NewPatientInfo.PATIENT_FNAME, PatientInfo.NewPatientInfo.PATIENT_LNAME, PatientInfo.NewPatientInfo.PATIENT_DEPARTMENT};
cursor = db.query(PatientInfo.NewPatientInfo.TABLE_NAME,projections,null,null,null,null,null);
return cursor;
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
}
}
PatientInfo.java // 这是列名等等。
package tanav.sharma;
/**
* Created by Tanav on 11/4/2016.
*/
public class PatientInfo {
public static abstract class NewPatientInfo{
//public static final String PATIENT_ID = "patient_id";
public static final String PATIENT_FNAME = "patient_fname";
public static final String PATIENT_LNAME = "patient_lname";
public static final String PATIENT_DEPARTMENT = "patient_department";
public static final String TABLE_NAME = "patient_info";
}
}
PatientInfoProvider.java
package tanav.sharma;
/**
* Created by Tanav on 11/4/2016.
*/
public class PatientInfoProvider {
private String fname;
private String lname;
private String departments;
public PatientInfoProvider(String fname, String lname, String departments){
this.fname = fname;
this.lname = lname;
this.departments = departments;
}
public String getLname() {
return lname;
}
public void setLname(String lname) {
this.lname = lname;
}
public String getDepartments() {
return departments;
}
public void setDepartments(String departments) {
this.departments = departments;
}
public String getFname() {
return fname;
}
public void setFname(String fname) {
this.fname = fname;
}
}
下面的文件是用 customText 视图在 listView 中显示值。
PatientAdapter.java
package tanav.sharma;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.TextView;
import java.util.ArrayList;
import java.util.List;
/**
* Created by Tanav on 11/4/2016.
*/
public class PatientAdapter extends ArrayAdapter {
List list = new ArrayList();
public PatientAdapter(Context context, int resource) {
super(context, resource);
}
static class LayoutHandler{
TextView FNAME,LNAME,Department;
}
@Override
public void add(Object object) {
super.add(object);
list.add(object);
}
@Override
public int getCount() {
return list.size();
}
@Override
public Object getItem(int position) {
return list.get(position);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View row = convertView;
LayoutHandler layoutHandler;
if(row == null){
LayoutInflater layoutInflater = (LayoutInflater)this.getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
row = layoutInflater.inflate(R.layout.display_all_patients,parent,false);
layoutHandler = new LayoutHandler();
layoutHandler.FNAME = (TextView)row.findViewById(R.id.patientNameFirst);
layoutHandler.LNAME = (TextView)row.findViewById(R.id.patientNameLast);
layoutHandler.Department = (TextView) row.findViewById(R.id.patientDepartment);
row.setTag(layoutHandler);
}else{
layoutHandler = (LayoutHandler)row.getTag();
}
PatientInfoProvider patientInfoProvider = (PatientInfoProvider)this.getItem(position);
layoutHandler.FNAME.setText(patientInfoProvider.getFname());
layoutHandler.LNAME.setText(patientInfoProvider.getLname());
layoutHandler.Department.setText(patientInfoProvider.getDepartments());
return row;
}
}
【问题讨论】：
-
developer.android.com/reference/android/provider/…。检查_ID。您可以使用
BaseColumns._ID并使其成为INTEGER NOT NULL PRIMARY KEY -
我会把这个放在哪里？在我的 PatientDbHelper 中？
-
是的
"CREATE TABLE "+PatientInfo.NewPatientInfo.TABLE_NAME+" (" + BaseColumns._ID + " INTEGER NOT NULL PRIMARY KEY,"...... -
好的，已经成功了。有什么方法可以私信你吗？我还有更多问题
-
您可以在 stackoverflow 上加入聊天室。但是有一些规则需要遵守。你需要问一个新问题
标签： java android sql sqlite android-studio