如何创建一个新线程，Android Studio？

Question

我有以下片段类：

public class fragment1 extends Fragment {
    private TextView bunz_count;
    private TextView money_count;
    private Bunz bunz;
    private Handler handler;
    int delay = 1000;
    View view;
    @Nullable
    @Override
    public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        bunz = Bunz.getInstance();
        handler = new Handler();


        view = inflater.inflate(R.layout.fragment1, container, false);


        handler.postDelayed(new Runnable(){
            public void run(){
                update(view);
                handler.postDelayed(this, delay);
            }
        }, delay);







        return view;
    }


    public void update(View view){
        bunz_count = (TextView) view.findViewById(R.id.final_bunz_count);
        money_count = (TextView) view.findViewById(R.id.final_money_count);
        //System.out.println(bunz.getBaker1());


        BigDecimal number = ((BigDecimal.valueOf
                (bunz.getBaker1()).multiply(BigDecimal.valueOf(.1))));
//        ).add((BigDecimal.valueOf(bunz.getBaker2()).multiply(BigDecimal.valueOf(.2)))).
//                add((BigDecimal.valueOf
//                        (bunz.getBaker3()).multiply(BigDecimal.valueOf(.4)))).
//                add((BigDecimal.valueOf
//                        (bunz.getBaker4()).multiply(BigDecimal.valueOf(.8)))).
//                add((BigDecimal.valueOf(bunz.getBaker5()).multiply(BigDecimal.valueOf(1)))).
//                add((BigDecimal.valueOf(bunz.getBaker6()).multiply(BigDecimal.valueOf(2)))).
//                add((BigDecimal.valueOf(bunz.getBaker7()).multiply(BigDecimal.valueOf(4)))).
//                add((BigDecimal.valueOf(bunz.getBaker8()).multiply(BigDecimal.valueOf(5)))).
                //add((BigDecimal.valueOf(bunz.getBaker9()).multiply(BigDecimal.valueOf(10))));
        //System.out.println(number);
        bunz.setBunz(bunz.getBunz().add((number)));
        bunz_count.setText("Bunz: " + bunz.getBunz());
        money_count.setText("Money: " + bunz.getMoney());
        System.out.println("bunz" + bunz.getBunz());

    }
}

更新玩家货币的 UI 显示。但是，由于在后台运行了许多不同的进程，因此该线程滞后并且存在问题。如何在单独的线程上运行它以避免这种情况？

编辑：我尝试过这样的事情：

        mHandlerThread = new HandlerThread("yeye");
        mHandlerThread.start();
        handler = new Handler(mHandlerThread.getLooper());
        handler.postDelayed(new Runnable(){
            public void run(){
                update(view);
                handler.postDelayed(this, delay);
            }
        }, delay);

但它没有帮助！

谢谢！

Answer 1

我也遇到了同样的问题。

我的问题的解决方案是创建 3 个可运行文件并在 onCreate() 方法中启动它们。

看起来是这样的：

Thread thread = new Thread(runnable);
thread.start();

为了创建可运行的“对象”，只需执行以下操作：

Runnable runnable = new Runnable(){
    public void run() {   
       //some code here
    }
}; 

如果您想要一些延迟的操作，您可以在可运行界面中使用延迟的帖子（注意，postDelayed() 只会重复整个可运行。您可以通过添加一些条件来避免这种情况）

Runnable runnable = new Runnable(){
    public void run() {   
       //some code here
       handler.postDelayed(this, 1000);
    }
}; 

如果你想更新 GUI，你应该在你的 runnable 中调用以下命令：

handler.post(new Runnable() {
     @Override
     public void run () {
     // upate textFields, images etc...

     }
});

附：如果您有多个线程并且它们必须在不同的时间启动，您可以从 Runnables 启动它们。

一些有用的页面：

new Runnable() but no new thread?

What's the difference between Thread start() and Runnable run()

How to run a Runnable thread in Android at defined intervals?

When to use handler.post() & when to new Thread()