【问题标题】:Servlet get parameter from multipart form in tomcat 7 [duplicate]Servlet从tomcat 7中的多部分表单获取参数[重复]
【发布时间】:2013-03-21 17:17:51
【问题描述】:

制作项目需要文件上传。 所以,我正在使用 enctype="multipart/form-data" 通知。

但我无法解析请求中的参数。 我也试过 getPart 但它返回空白字符串。

Servlet 代码 -->

import java.io.File;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.List;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;

public class upload_wall extends HttpServlet {
    private static final long serialVersionUID = 1L;
    // location to store file uploaded
    private static final String UPLOAD_DIRECTORY = "image_upload";
    // upload settings
    private static final int MEMORY_THRESHOLD = 1024 * 1024 * 3;  // 3MB
    private static final int MAX_FILE_SIZE = 1024 * 1024 * 40; // 40MB
    private static final int MAX_REQUEST_SIZE = 1024 * 1024 * 50; // 50MB

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        response.setContentType("text/html");
        PrintWriter out = response.getWriter();

        // checks if the request actually contains upload file
        if (!ServletFileUpload.isMultipartContent(request)) {
            // if not, we stop here
            PrintWriter writer = response.getWriter();
            writer.println("Error: Form must has enctype=multipart/form-data.");
            writer.flush();
            return;
        }

        // configures upload settings
        DiskFileItemFactory factory = new DiskFileItemFactory();
        // sets memory threshold - beyond which files are stored in disk
        factory.setSizeThreshold(MEMORY_THRESHOLD);
        // sets temporary location to store files
        factory.setRepository(new File(System.getProperty("java.io.tmpdir")));

        ServletFileUpload upload = new ServletFileUpload(factory);

        // sets maximum size of upload file
        upload.setFileSizeMax(MAX_FILE_SIZE);

        // sets maximum size of request (include file + form data)
        upload.setSizeMax(MAX_REQUEST_SIZE);

        // constructs the directory path to store upload file
        // this path is relative to application's directory
        String uploadPath = getServletContext().getRealPath("") + File.separator + UPLOAD_DIRECTORY;

        // creates the directory if it does not exist
        File uploadDir = new File(uploadPath);
        if (!uploadDir.exists()) {
            uploadDir.mkdir();
        }

        try {
            @SuppressWarnings("unchecked")
            List<FileItem> formItems = upload.parseRequest(request);
            String fileName1 = "";
            if (formItems != null && formItems.size() > 0) {
                for (FileItem item : formItems) {
                    // processes only fields that are not form fields
                    if (!item.isFormField()) {
                        String fileName = new File(item.getName()).getName();
                        fileName1 += fileName;
                        String filePath = uploadPath + File.separator + fileName;
                        File storeFile = new File(filePath);
                        // saves the file on disk
                        item.write(storeFile);
                    }
                }
            }
            String p_text = request.getParameter("p_data");
            String gallery_nm = request.getParameter("upload_wall_gallery");
            out.println(p_text);
            out.println(gallery_nm);
            //out.println("Upload has been done successfully!"+fileName1);
        } catch (Exception ex) {
            out.println(ex.getMessage());
        }

    }

}

我在 net 或 stackoverflow 上找不到工作示例。

有什么简单的解决办法吗?

【问题讨论】:

    标签: java jsp tomcat servlets getparameter


    【解决方案1】:

    由于它是 multipart/form-data 形式,因此对 request.getParameter() 的调用将始终返回 null。在这种情况下,您要做的是

     if (item.isFormField()) {
         System.out.println("Got a form field: " + item.getFieldName()+ " " +item.getString());
     } else {
         // it is a file process, the way you are doing it
     }
    

    我希望一切正常。

    【讨论】:

    • 如果它对您有用,您可以接受并投票赞成这个答案。它将帮助未来的用户:)。
    【解决方案2】:

    问题出在这里:

    String p_text = request.getParameter("p_data");
    String gallery_nm = request.getParameter("upload_wall_gallery");
    

    How to upload files to server using JSP/Servlet? answer,您应该将参数设置为FileItem,其中isFormField() 方法返回true。贴出答案中的相关代码片段:

    for (FileItem item : formItems) {
        if (item.isFormField()) {
            // Process regular form field (input type="text|radio|checkbox|etc", select, etc).
            String fieldname = item.getFieldName();
            String fieldvalue = item.getString();
            // ... (do your job here)
        } else {
            // Process form file field (input type="file").
            String fieldname = item.getFieldName();
            String filename = FilenameUtils.getName(item.getName());
            InputStream filecontent = item.getInputStream();
            // ... (do your job here)
        }
    }
    

    解决方案:在调用if (!item.isFormField()) 时,将您的其他请求参数处理移至else 部分。

    for (FileItem item : formItems) {
        // processes only fields that are not form fields
        if (!item.isFormField()) {
            String fileName = new File(item.getName()).getName();
            fileName1+=fileName;
            String filePath = uploadPath + File.separator + fileName;
            File storeFile = new File(filePath);
            // saves the file on disk
            item.write(storeFile);
        } else {
            //here...
            String fieldname = item.getFieldName();
            String fieldvalue = item.getString();
            if (fieldname.equals("p_data")) {
                //logic goes here...
            } else if (fieldname.equals("upload_wall_gallery")) {
                //next logic goes here...
            }
        }
    }
    

    【讨论】:

    • @LovepreetSinghBatth,因为您是新来的,请点击声誉下方的检查,将此帖子标记为答案。
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