【发布时间】:2015-09-19 09:57:56
【问题描述】:
目前正在开发 jquery clone 和 datepicker,它将计算日期并检查重叠日期。但是,如果单击 less 按钮,代码可以正常工作,它正在删除该行,但它没有检测到克隆 div 中存在的日期。例如,当用户为此选择日期 10-01-1990 和 10-01-1995 时,总数为 Total work experience 5 years 0 Months & 如果用户给出了 10-01-1996 和 10-01-2015,则在克隆的 div 中,因此总数为 25 年 0 个月的总工作经验。如果用户单击 lessbtn 按钮,克隆的将删除但总年份未检测到。
这里是jquery代码
$(document).on('change', ".datepicker", function (){
var valid=true;
$.each($('.datepicker'),function(){
if($(this).val()=="")
{
valid=false;
return false;
}
});
if(valid)
{
var dateStart=[];
var dateEnd=[];
$.each($('.datepicker'),function(){
if($(this).hasClass('startDate'))
dateStart.push($(this).val())
else
dateEnd.push($(this).val())
});
$.each($(dateStart),function(key,value){
var x = dateStart[key].split("-");
var y = dateEnd[key].split("-");
var failed = false;
var fromdate = new Date(x[2], x[0] - 1, x[1]);
var todate = new Date(y[2], y[0] - 1, y[1]);
var locDiffDays = parseInt((todate.getTime() - fromdate.getTime()) / (1000 * 60 * 60 * 24));
console.log(x);
console.log(y);
console.log(fromdate);
console.log(todate);
console.log(locDiffDays);
if(locDiffDays<0){
alert("To date " + dateEnd[key] + " should be greater then from date " + dateStart[key] );
console.log("invalid from and to dates"); failed = true; return false;
}
if(dateStart[key-1]){
var x1 = dateStart[key-1].split("-");
var y1 = dateEnd[key-1].split("-");
var fromdate1 = new Date(x1[2], x1[0] - 1, x1[1]);
var todate1 = new Date(y1[2], y1[0] - 1, y1[1]);
var locDiffDays1 = parseInt((todate1.getTime() - fromdate1.getTime()) / (1000 * 60 * 60 * 24));
console.log(x1);
console.log(y1);
console.log(fromdate1);
console.log(todate1);
console.log(locDiffDays1);
var locDiffDays2 = parseInt((fromdate.getTime() - fromdate1.getTime()) / (1000 * 60 * 60 * 24));
var locDiffDays3 = parseInt((todate.getTime() - todate1.getTime()) / (1000 * 60 * 60 * 24));
var locDiffDays4 = parseInt((fromdate.getTime() - todate1.getTime()) / (1000 * 60 * 60 * 24));
console.log("locDiffDays2: " + locDiffDays2);
if(locDiffDays2<0){
alert("From date " + dateStart[key] + " should be greater than previous from date " + dateStart[key-1] );
console.log("invalid from dates"); failed = true; return false;
}
if(locDiffDays3<0){
alert("To date " + dateStart[key] + " should be greater than previous To date " + dateStart[key-1] );
console.log("invalid from dates"); failed = true; return false;
}
if(locDiffDays4<0){
alert("From date " + dateStart[key] + " should be greater than previous To date " + dateEnd[key-1] );
console.log("invalid from dates"); failed = true; return false;
}
}
if(key == dateStart.length-1 && !failed){
var firstDate = dateStart[0].split('-');
firstDate = new Date(firstDate[2], firstDate[0] - 1, firstDate[1]);
var lastDate = dateEnd[dateEnd.length-1].split('-');
lastDate = new Date(lastDate[2], lastDate[0] - 1, lastDate[1]);
console.log(lastDate);
console.log(firstDate);
//var diffYears = (lastDate.getTime() - firstDate.getTime()) / (1000 * 60 * 60 * 24 * 365);
var diffMonths = monthDiff(firstDate, lastDate);
//diffYears = parseInt(''+diffYears);
var diffYears = diffMonths/12;
diffYears = parseInt(''+diffYears);
diffMonths = diffMonths - (diffYears * 12)
document.getElementById("txt_expy").innerHTML = diffYears + " years";
document.getElementById("txt_expm").innerHTML = diffMonths + " Months";
}
});
请给我建议。
我在这里感到困惑,我想输入任何计数或其他内容,因此当用户单击较少按钮时,计数应该减少一个并且应该检测到该值。请在这里给我提示
这是小提琴Link
感谢和问候
【问题讨论】:
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请有任何建议
标签: javascript jquery html jquery-ui jquery-ui-datepicker