【发布时间】:2023-03-10 09:40:01
【问题描述】:
我正在尝试解析一个 JSON 对象,其中一部分如下所示:
{
"offer":{
"category":"Salon",
"description":"Use this offer now to enjoy this great Salon at a 20% discount. ",
"discount":"20",
"expiration":"2011-04-08T02:30:00Z",
"published":"2011-04-07T12:00:33Z",
"rescinded_at":null,
"title":"20% off at Jun Hair Salon",
"valid_from":"2011-04-07T12:00:31Z",
"valid_to":"2011-04-08T02:00:00Z",
"id":"JUN_HAIR_1302177631",
"business":{
"name":"Jun Hair Salon",
"phone":"2126192989",
"address":{
"address_1":"12 Mott St",
"address_2":null,
"city":"New York",
"cross_streets":"Chatham Sq & Worth St",
"state":"NY",
"zip":"10013"
}
},
等等……
到目前为止,我可以通过做这样的事情来非常简单地解析:
JSONObject jObject = new JSONObject(content);
JSONObject offerObject = jObject.getJSONObject("offer");
String attributeId = offerObject.getString("category");
System.out.println(attributeId);
String attributeValue = offerObject.getString("description");
System.out.println(attributeValue);
String titleValue = offerObject.getString("title");
System.out.println(titleValue);`
但是当我尝试使用 'name:' 时,它不起作用。
我试过了:
JSONObject businessObject = jObject.getJSONObject("business");
String nameValue = businesObject.getString("name");
System.out.println(nameValue);
当我尝试这样做时,我得到“未找到 JSONObject [business]”。
当我尝试时:
String nameValue = offerObject.getString("name");
System.out.println(nameValue);`
正如预期的那样,我得到“未找到 JSONObject [name]”。
我在这里做错了什么?我缺少一些基本的东西......
【问题讨论】:
-
嗨,我刷新了以下页面并得到了解决方案stackoverflow.com/questions/5986123/…