获取异常：org.json.JSONObject 无法转换为 JSONArray

Question

我是一名 android 初学者，请为此提供必要的帮助。

try {
 JSONArray jArray = new JSONArray(result);
 // Extract data from json and store into ArrayList as class objects
 for (int i = 0; i < jArray.length(); i++) {
  JSONObject json_data = jArray.getJSONObject(i);
  DataFish fishData = new DataFish();
  fishData.nonce = json_data.getString("nonce");
  fishData.iUserId = json_data.getString("iUserId");
  fishData.timestamp = json_data.getString("timestamp");
  fishData.token = json_data.getString("token");

  data.add(fishData);
 }

 // Setup and Handover data to recyclerview
 mRVFishPrice = (RecyclerView) findViewById(R.id.fishPriceList);
 mAdapter = new AdapterFish(PostActivity.this, data);
 mRVFishPrice.setAdapter(mAdapter);
 mRVFishPrice.setLayoutManager(new LinearLayoutManager(PostActivity.this));

} 
catch (JSONException e) {
 Toast.makeText(PostActivity.this, e.toString(), Toast.LENGTH_LONG).show();
}

我已将其转换为 JSONArray，但我仍在获取

org.json.JSONException: Value {"code":"0","message":"拒绝访问， org.json.JSONObject 类型的无效用户引用"} 不能是 转换为 JSONArray。

Answer 1

这不是 JSONArray 对象。它是一个 JSONObject，你不能将它解析为 JSONArray。如需更多参考，您可以查看it here。

Answer 2

试试吧。

JSONArray alldata = new JSONArray();

for(your codition to get data for how many array items in loop){
JSONObject all = new JSONObject(); 
all.put("nonce", "G9Ivek");
all.put("iUserId", "477");
all.put("timestamp","20160614060439");
alldata.put(all);

}

并将所有数据发送到服务器。

希望这会对你有所帮助..让我知道..

发送到服务器

JSONObject objMainList = new JSONObject();
objMainList.put("ALLDETAILS", alldata);

用于在 ASYNC TASK DOINBACKGROUND() 中与 api url 绑定日期

Map<String, String> param = new HashMap<String, String>();
                    param.put("access_code", access_code);
                    param.put("auth_token", auth_token);
                    param.put("data", objMainList.toString());

                    try {
                        HttpUtility.sendPostRequest(Config.Submit_Answer, param);
                        String response = HttpUtility.readMultipleLinesRespone();
                        json = new JSONObject(response);
                        HttpUtility.disconnect();

} catch (Exception e) {

                        e.printStackTrace();

                    }