【发布时间】:2014-08-27 05:36:10
【问题描述】:
我有一个解析器,它将一个值作为字符串抓取,如果它不等于预期值,则调用以下函数。只有下面的函数什么都不做,它到达 builder.show() 然后跳回我的解析器。它没有显示对话框,因为如果选择了OK按钮时它会在委托时击中委托()。关于可能导致此问题的任何想法。我不知道我是否有一些语法错误或问题是什么?我感谢任何和所有的帮助。
private void errorReturnReader(string val)
{
string message = "";
if (val != "")
{
AlertDialog.Builder builder;
builder = new AlertDialog.Builder (this,3);
builder.SetTitle("Institution Status Error");
builder.SetCancelable(false);
builder.SetPositiveButton("OK", delegate { Finish(); });
switch (val)
{
case "NO_KEY":
message = "The Key passed does not exist.";
break;
case "NO_EMP":
message = "The employee id does not exist in the specified institution.";
break;
case "NO_INST":
message = "The Institution code associated with key does not exist.";
break;
case "NO_BRANCH":
message = "The Branch value passed does not exist.";
break;
case "EMP_EXCL":
message = "Employee is excluded from all branches.";
break;
case "NO_STAT":
message = "No audit records were found for the branch.";
break;
case "NO_RESPONSE":
message = "No status was returned";
break;
case "NO_COMM":
message = "The Cloud has not communicated with the Console within 60 seconds. Can not verify status.";
break;
default:
break;
}
builder.SetMessage(message);
builder.Create ();
builder.Show ();
}
}
【问题讨论】:
-
试试这个:builder.Create().show();
-
我在发布之前也尝试过,它并没有改变结果。感谢您的回复。
标签: c# android android-alertdialog