【发布时间】:2010-10-12 03:06:55
【问题描述】:
我的问题是我之前有一个程序工作,没有线程,处理信息需要很长时间(16 秒才能获取 XML 数据并显示它)。现在我已经完成了整个线程和异步操作,但是由于某种原因,它使我的程序变慢了(在模拟器中,设备现在不可用),我所做的任何事情都可能导致这种情况, UI 线程很好,但我的异步线程需要一分半钟才能执行。 (当我在 UI 线程中使用它时只需要 16 秒,但冻结了 UI 线程)
这是我的线程的代码,它位于主类中:
private class TeamSearchTask extends AsyncTask<String,Void,String> {
CharSequence nfo;
String [] matches;
String [] data;
String teamNum;
ProgressDialog loading;
protected void onPreExecute()
{
//Show the 'loading' dialog
loading = new ProgressDialog(SapphireAlliance.this);
loading.setMessage("Loading, please wait...");
loading.show();
}
protected String doInBackground(String... teamNumber)
{
try
{
//Team information ------------------------------------------------------------------------------------
teamNum = teamNumber[0];
//Array of team data
data = APIconnection.getTeams(teamNum, "");
//Display basic team info
nfo = ("\nFormal Team Name:\n" + data[1] +
"\n\nLocation:\n" + data [3] + ", " + data[4] + ", " + data[5] +
"\n\nRookie Year:\n" + data[6] +
"\n\nRobot Name:\n" + data[7] +
"\n\nWebsite:\n" + data[8] + "\n\n\n\n\n\n\n\n\n");
//Make match archive --------------------------------------------------------------------------------------
String [] events = APIconnection.getEventIdsByYear(year1);
ArrayList<String> matches = new ArrayList<String>();
for (int i = 0; i<events.length; i++)
{
String [] add = APIconnection.getMatches2(teamNum, events[i] ,"","");
for(int j = 0; j<add.length; j++)
matches.add(add[j]);
}
String [] out = new String [matches.size()];
matches.toArray(out);
return "";
}
catch(Exception e)
{
return e.toString();
}
}
protected void onPostExecute(String result) {
if(result.equals(""))
{
info.setText(nfo);
matchArchive(matches);
//title
CharSequence ttl = "Team " + teamNum;
titlets.setText(ttl.toString());
loading.dismiss();
}
else
{
alert.setMessage(result);
alert.show();
}
}
}
里面有什么可能导致这种情况的吗? :|
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