【发布时间】:2012-02-18 13:16:22
【问题描述】:
我有以下四张表:
SCHEDULE_REQUEST 表: ID, APPLICATION_ID (FK)
应用表: ID, 代码
USER_APPLICATION 表: APPLICATION_ID (FK), USER_ID (FK)
用户表: ID, 姓名
现在我想创建一个CriteriaBuilder,其中条件是为指定的用户 ID 选择 ScheduleRequests。
我有以下代码:
List<User> usersList = getSelectedUsers(); // userList contains users I wanted to select
CriteriaBuilder builder = getJpaTemplate().getEntityManagerFactory().getCriteriaBuilder();
CriteriaQuery<ScheduleRequest> criteria = builder.createQuery(ScheduleRequest.class);
Root<ScheduleRequest> scheduleRequest = criteria.from(ScheduleRequest.class);
criteria = criteria.select(scheduleRequest);
ParameterExpression<User> usersIdsParam = null;
if (usersList != null) {
usersIdsParam = builder.parameter(User.class);
params.add(builder.equal(scheduleRequest.get("application.userApplications.user"), usersIdsParam));
}
criteria = criteria.where(params.toArray(new Predicate[0]));
TypedQuery<ScheduleRequest> query = getJpaTemplate().getEntityManagerFactory().createEntityManager().createQuery(criteria);
// Compile Time Error here:
// The method setParameter(Parameter<T>, T) in the type TypedQuery<ScheduleRequest> is not
// applicable for the arguments (ParameterExpression<User>, List<User>)
query.setParameter(usersIdsParam, usersList);
return query.getResultList();
您能帮我如何将查询过滤器传递给关系对象吗? 我认为我在 "application.userApplications.user" 中所做的事情是错误的? 请真的需要帮助。
提前谢谢你!
【问题讨论】:
标签: java hibernate jpa filter criteria