【发布时间】:2019-09-29 05:01:11
【问题描述】:
我有以下 JPA 实体
@Entity
class UserEntity {
companion object {
fun fromParameters(uuid: String, email: String, password: String, firstName: String, lastName: String) =
UserEntity().apply {
this.uuid = uuid
this.email = email
this.password = password
this.firstName = firstName
this.lastName = lastName
}
}
@Id
lateinit var uuid: String
@Column(nullable = false, unique = true)
lateinit var email: String
@Column(nullable = false)
lateinit var password: String
@Column(nullable = false)
lateinit var firstName: String
@Column(nullable = false)
lateinit var lastName: String
}
这是我检查 UNIQUE 约束的测试,使用相同的电子邮件插入另一个用户。
@RunWith(SpringRunner::class)
@DataJpaTest
@AutoConfigureTestEntityManager
class TestUserCrudRepository {
@Autowired
private lateinit var userCrudRepository: UserCrudRepository
private val testUserEntity = UserEntity.fromParameters(
UUID.randomUUID().toString(),
"test@test.com",
"password".toHash(),
"Caetano",
"Veloso"
)
@Test
fun `when email already exists it should throw error`() {
with (userCrudRepository) {
save(testUserEntity)
val newUserEntity = with (testUserEntity) { UserEntity.fromParameters(UUID.randomUUID().toString(), email, password, firstName, lastName) }
shouldThrow<SQLException> { save(newUserEntity) }
}
}
}
插入新实体时总是带有重复的电子邮件,不会引发任何异常。
Expected exception java.sql.SQLException but no exception was thrown
我可以在日志中看到使用给定约束正确创建了表。
Hibernate: drop table user_entity if exists
Hibernate: create table user_entity (uuid varchar(255) not null, email varchar(255) not null, first_name varchar(255) not null, last_name varchar(255) not null, password varchar(255) not null, primary key (uuid))
Hibernate: alter table user_entity add constraint UK_4xad1enskw4j1t2866f7sodrx unique (email)
提前致谢!
【问题讨论】:
标签: hibernate spring-boot kotlin spring-data-jpa h2