【发布时间】:2014-07-26 04:53:25
【问题描述】:
我正在开发一个 android 应用程序,我从 mysql 数据库中获取数据并在 Listview 中显示该数据。我有电信、银行、社交网站等数据“类别”。这个从 mysql 获取的 Category 完美地显示在 ListView 中。现在,当我单击其中任何一个时,它应该移动到下一个活动并根据该类别显示数据。假设我点击社交网站,然后在下一个活动中,数据应该是 Google Plus、Instagram、Twitter 等,这个列表将来自数据库并显示在列表视图中。我不知道该怎么做..!!!请帮助我...这是我所做的代码。
Welcome.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.os.StrictMode;
import android.util.Log;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.ListView;
import android.widget.TextView;
public class Welcome extends Activity
{
TextView text;
//Button b1,b2,b3;
String CompName,CompID;
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_welcome);
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
// b1=(Button)findViewById(R.id.dashboard_tab1);
// b1.setOnClickListener(this);
connect();
}
public void connect()
{
String data;
List<String> r = new ArrayList<String>();
ArrayAdapter<String>adapter=new ArrayAdapter<String>(getApplicationContext(), android.R.layout.simple_list_item_1,r);
ListView list=(ListView)findViewById(R.id.list);
try
{
DefaultHttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet("http://10.0.2.2/database/Retrive.php");
HttpResponse response = client.execute(request);
HttpEntity entity=response.getEntity();
data=EntityUtils.toString(entity);
Log.e("STRING", data);
try
{
JSONArray json=new JSONArray(data);
for(int i=0;i<json.length(); i++)
{
JSONObject obj=json.getJSONObject(i);
CompName=obj.getString("fldCompName");
CompID=obj.getString("fldCompID");
Log.e("STRING", CompName);
Log.e("STRING",CompID);
r.add(CompName);
//r.add(CompID);
list.setAdapter(adapter);
list.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener()
{
@Override
public void onItemClick(AdapterView<?> parent,View view, int position, long id)
{
Intent i1=new Intent(Welcome.this,Category1.class);
i1.putExtra("CompName", CompName);
startActivity(i1);
}
});
}
}
catch (JSONException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
} catch (ClientProtocolException e) {
Log.d("HTTPCLIENT", e.getLocalizedMessage());
} catch (IOException e) {
Log.d("HTTPCLIENT", e.getLocalizedMessage());
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu)
{
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.welcome, menu);
return true;
}
}
这是我的布局文件...!!!
activity_welcome.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
xmlns:android="http://schemas.android.com/apk/res/android">
<ListView
android:id="@+id/list"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:background="@drawable/bg" >
</ListView>
</LinearLayout>
Retrive.php
<?php
$host='localhost';
$uname='root';
$pwd='';
$db='database';
$con=mysqli_connect($host,$uname,$pwd) or die("Connection Failed");
mysqli_select_db($con,$db) or die("database selection failed");
$sql=mysqli_query($con,"select fldCompName,fldCompID from tblCompanies where fldStatus='1'");
while($row=mysqli_fetch_assoc($sql))
$output[]=$row;
$a=json_encode($output);
print($a);
mysqli_close();
?>
【问题讨论】:
-
您是否获得了所有数据?我的意思是,您的所有数据都在 1 个表中,或者在不同表中的类别明智?
标签: php android mysql json listview