如何传递 jsonEncode http post？答案

【问题标题】：how to pass jsonEncode http post?如何传递 jsonEncode http post？
【发布时间】：2021-12-28 09:49:20
【问题描述】：

我得到了所有参数 jsonEncode 然后我将通过 http post。我已经在下面通过源代码进行了解释。

 var abc =  jsonEncode({
        "requisitionID": "x",
        "RetailerTitle": "Faruqe Ahmed  Store",
        "RetailerAddress" : "Dhaka Nilkhet",
        "Market": "Nilkhet",
        "RetailerAreaType":"R",
        "RetailerType":"R",
        "RetailerProprieterName": "Faruqe Ahmed",
        "RetailerContactNumber": "01736611372",
        "Longitude": "Longitude",
        "Lattitude": "Lattitude",
        "Thana": {"ThanaID": "Shahbag"},
        "District": {"DistrictID": "Dhaka"},
        "EntryParameter": {"CompanyID": "x"},
        "EntryParameter": {"LocationID": "x"},
        "EntryParameter": {"MachineID": "x"},
        "EntryParameter": {"EntryBy": "D180064"},
        "EntryParameter": {"UpdateBy": "x"},
        "ImageFieldBanner": ""
      }),

但是当我从 print(abc .toString()) 获取字符串时。然后我只有

{
        "requisitionID": "x",
        "RetailerTitle": "Faruqe Ahmed  Store",
        "RetailerAddress" : "Dhaka Nilkhet",
        "Market": "Nilkhet",
        "RetailerAreaType":"R",
        "RetailerType":"R",
        "RetailerProprieterName": "Faruqe Ahmed",
        "RetailerContactNumber": "01736611372",
        "Longitude": "Longitude",
        "Lattitude": "Lattitude",
        "Thana": {"ThanaID": "Shahbag"},
        "District": {"DistrictID": "Dhaka"},
        "EntryParameter": {"UpdateBy": "x"},
        "ImageFieldBanner": ""
      }

跳过

   "EntryParameter": {"CompanyID": "x"},
        "EntryParameter": {"LocationID": "x"},
        "EntryParameter": {"MachineID": "x"},
        "EntryParameter": {"EntryBy": "D180064"},

我需要

{
        "requisitionID": "x",
        "RetailerTitle": "Faruqe Ahmed  Store",
        "RetailerAddress" : "Dhaka Nilkhet",
        "Market": "Nilkhet",
        "RetailerAreaType":"R",
        "RetailerType":"R",
        "RetailerProprieterName": "Faruqe Ahmed",
        "RetailerContactNumber": "01736611372",
        "Longitude": "Longitude",
        "Lattitude": "Lattitude",
        "Thana": {"ThanaID": "Shahbag"},
        "District": {"DistrictID": "Dhaka"},
        "EntryParameter": {"CompanyID": "x"},
        "EntryParameter": {"LocationID": "x"},
        "EntryParameter": {"MachineID": "x"},
        "EntryParameter": {"EntryBy": "D180064"},
        "EntryParameter": {"UpdateBy": "x"},
        "ImageFieldBanner": ""
      }

【问题讨论】：

标签： android json flutter http jsonencoder

【解决方案1】：

你给 jsonEncode 方法的参数是一个 Map，一个 map 使用唯一的键来访问它的值。

您的地图多次使用“EntryParameter”键，这会导致同一个值被多次覆盖，而只保留最后一个值。

要解决这个问题，如果输出结构很重要，您可能需要将键值对放在一个数组中并自己创建所需的 json 代码。

示例

未经测试的代码，但应该清楚如何做到这一点，变量 jsonManualData 应该包含您需要的确切 json 字符串：

Map<String, dynamic> data = {
  "requisitionID": "x",
  "RetailerTitle": "Faruqe Ahmed  Store",
  "RetailerAddress": "Dhaka Nilkhet",
  "Market": "Nilkhet",
  "RetailerAreaType": "R",
  "RetailerType": "R",
  "RetailerProprieterName": "Faruqe Ahmed",
  "RetailerContactNumber": "01736611372",
  "Longitude": "Longitude",
  "Lattitude": "Lattitude",
  "Thana": {"ThanaID": "Shahbag"},
  "District": {"DistrictID": "Dhaka"},
  "EntryParameter": [
    {"CompanyID": "x"},
    {"LocationID": "x"},
    {"MachineID": "x"},
    {"EntryBy": "D180064"},
    {"UpdateBy": "x"},
  ],
  "ImageFieldBanner": ""
};

String jsonData = jsonEncode(data);
String jsonManualData = "{${data.entries.map((e) => '"${e.key}": ${jsonEncode(e.value)}').join(",")}}";

【讨论】：

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