【发布时间】：2016-05-24 16:28:43
【问题描述】：
我正在尝试在 SQLiteDatabase 中存储一些信息。 当我调用方法插入时，它返回-1。所以发生了错误，但我无法弄清楚是什么问题。
代码如下：
public class SQLiteHandler extends SQLiteOpenHelper {
private static final String TAG = SQLiteHandler.class.getSimpleName();
// All Static variables
// Database Version
private static final int DATABASE_VERSION = 1;
// Database Name
private static final String DATABASE_NAME = "Find";
// Login table name
private static final String TABLE_USER = "user";
// Login Table Columns names
private static final String KEY_ID = "id";
private static final String KEY_NAME = "name";
private static final String KEY_LAST_NAME = "last_name";
private static final String KEY_EMAIL = "email";
private static final String KEY_BIRTHDAY = "birthday";
private static final String KEY_DESCRIPTION = "description";
private static final String KEY_CITY = "city";
private static final String KEY_UID = "uid";
private static final String KEY_CREATED_AT = "created_at";
public SQLiteHandler(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
// Creating Tables
@Override
public void onCreate(SQLiteDatabase db) {
String CREATE_LOGIN_TABLE = "CREATE TABLE " + TABLE_USER + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT,"
+ KEY_LAST_NAME + " TEXT," + KEY_EMAIL + " TEXT UNIQUE,"
+ KEY_BIRTHDAY + "TEXT" + KEY_DESCRIPTION + "TEXT"
+ KEY_CITY + "TEXT" + KEY_UID + " TEXT,"
+ KEY_CREATED_AT + " TEXT" + ")";
db.execSQL(CREATE_LOGIN_TABLE);
Log.d(TAG, "Database tables created");
}
// Upgrading database
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// Drop older table if existed
db.execSQL("DROP TABLE IF EXISTS " + TABLE_USER);
// Create tables again
onCreate(db);
}
/**
* Storing user details in database
*/
public void addUser(String name, String last_name, String email, String birthday, String description,
String city, String uid, String created_at) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(KEY_NAME, name); // Name
values.put(KEY_LAST_NAME, last_name); // Last Name
values.put(KEY_EMAIL, email); // Email
values.put(KEY_BIRTHDAY, birthday); // Birthday
values.put(KEY_DESCRIPTION, description); // Description
values.put(KEY_CITY, city); // City
values.put(KEY_UID, uid); // Unique ID
values.put(KEY_CREATED_AT, created_at); // Created at
// Inserting Row
long id = db.insert(TABLE_USER, null, values);
db.close(); // Closing database connection
Log.d(TAG, "New user inserted into sqlite: " + id);
}
/**
* Getting user data from database
*/
public HashMap<String, String> getUserDetails() {
HashMap<String, String> user = new HashMap<>();
String selectQuery = "SELECT * FROM " + TABLE_USER;
SQLiteDatabase db = this.getReadableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);
// Move to first row
cursor.moveToFirst();
if (cursor.getCount() > 0) {
user.put("name", cursor.getString(1));
user.put("last_name", cursor.getString(2));
user.put("email", cursor.getString(3));
user.put("birthday", cursor.getString(4));
user.put("description", cursor.getString(5));
user.put("city", cursor.getString(6));
user.put("uid", cursor.getString(7));
user.put("created_at", cursor.getString(8));
}
cursor.close();
db.close();
// return user
Log.d(TAG, "Fetching user from Sqlite: " + user.toString());
return user;
}
/**
* Re crate database. Delete all tables and create them again
*/
public void deleteUsers() {
SQLiteDatabase db = this.getWritableDatabase();
// Delete All Rows
db.delete(TABLE_USER, null, null);
db.close();
Log.d(TAG, "Deleted all user info from sqlite");
}
提前感谢您的帮助。
【问题讨论】：
-
你能发布堆栈跟踪吗？
-
可能因为一个值为 NULL 而失败？
-
@AndreaR.，一些事情。由于您可以发表评论，我建议您删除您的答案并通过 cmets 与我们交流。其次，您没有在表中指定
NOT NULL，所以null值应该没问题。 -
@AndreaR.，接下来，尝试删除应用程序并重新部署它，如果表创建不正确，这将使应用程序重新创建它。
-
伟大的团队合作@LucasPaolillo！
标签： android sqlite insert sql-insert