如何在一项 Android 活动中处理 2 个 Listvews答案

【问题标题】：How to handle 2 Listvews in one activity Android如何在一项 Android 活动中处理 2 个 Listvews
【发布时间】：2014-02-12 05:11:02
【问题描述】：

我在 1 个活动中创建了 2 个列表视图。

例如：蔬菜

 Fruits

 Meat

因此，当您单击水果时，我希望所有 5 种水果都显示在第二个列表视图中。你能告诉我怎么做吗？我的代码如下所示

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_listv);

    ListView menu= (ListView) findViewById(R.id.listView1);
    String items[]= {"Fruits","Vegetables","Jooses","Meat","Toys","Cookeys"};



ListView menu2= (ListView) findViewById(R.id.listView2);
    String subitems[]= {"xxx","xxx","xxx","xxx","xxx","xxx"};



    menu.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, items));
    menu2.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, subitems));

}

【问题讨论】：

您可以创建一个包含多列的列表视图。
@user3291365 这意味着我不必使用 2 个列表视图？实际上，我需要 2 个 ListVies，就像我在上面提到的那样。而且我也不想使用可扩展的列表视图。
@akunar ：请接受对您有帮助的答案
@user2450263 我怎样才能使用二维数组呢？我正在为此使用开关。现在我想通过二维数组传递数据
对于列表视图？自定义适配器...

标签： android android-intent android-listview

【解决方案1】：

在第一个listview的SetOnItemClick适配器中设置第二个listview的适配器：

menu.setOnItemClickListener(new OnItemClickListener() {
            public void onItemClick(AdapterView<?> parent, View view,
                    int position, long id) {
                // When clicked, check which item is it and then set adapter and display values in 2nd listview

            }
        });

参考：
http://matrix-examplecode.blogspot.in/2011/11/listview-example.html
http://www.mkyong.com/android/android-listview-example/
http://developer.android.com/reference/android/widget/AdapterView.html

【讨论】：

【解决方案2】：

## -----lets try this simple code. this will suites your need-----##

protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_listv);

ListView menu= (ListView) findViewById(R.id.listView1);
ListView menu2= (ListView) findViewById(R.id.listView2);
String items[]= {"Fruits","Vegetables","Jooses","Meat","Toys","Cookeys"};
String subitems1[]= {"xxx1","xxx","xxx","xxx","xxx","xxx"};
String subitems2[]= {"xxx2","xxx","xxx","xxx","xxx","xxx"};
String subitems3[]= {"xxx3","xxx","xxx","xxx","xxx","xxx"};
String subitems4[]= {"xxx4","xxx","xxx","xxx","xxx","xxx"};
String subitems5[]= {"xxx5","xxx","xxx","xxx","xxx","xxx"};
menu.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, items));
// on item click listener
menu.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,
                    long arg3) {

                // get the selected values from listview 1
                String val = items[arg2];

                if(val.equalsIgnoreCase("Fruits"))
                {
                // set the second listview 2 
                menu2.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, subitems1));
                }
                else if(val.equalsIgnoreCase("Vegetables"))
                {
                menu2.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, subitems2));
                }
                else if(val.equalsIgnoreCase("Jooses"))
                {
                menu2.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, subitems3));
                }
                else if(val.equalsIgnoreCase("Meat"))
                {
                menu2.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, subitems4));
                }
                else if(val.equalsIgnoreCase("Toys"))
                {
                menu2.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, subitems5));
                }

            }

    });

}

【讨论】：

【解决方案3】：

在菜单（Listview）上注册一个 onItemClickListener 回调。

menu.setOnItemClickListener(new OnItemClickListener()
{
  @Override
  public void onItemClick (AdapterView<?> parent, View view, int position,
      long id)
  {
    /* TODO: Update menu2 adapter items */
    /* Position - determines the item that is being clicked on your menu listview,
       by that. you can render your second adapter based on the item selected */

    /* Call adapter notifyDatasetChanged method to inform adapter that its data set
       has changed. */
    menu2Adapter.notifyDatasetChanged();
  }
});

或其他设计可能是。将您的第二个列表视图放在第二个活动上。每次你选择一个项目。推送指向第二个列表视图的新活动..

【讨论】：

【解决方案4】：

当您单击左侧列表视图中的项目时，将触发OnItemCLickListener。在回调中，更新第二个listview维护的底层数据，调用notifyDataSetChanged。

【讨论】：

【解决方案5】：

检查以下答案...我自己检查了此代码。可能是你想做的。

    ListView menu = (ListView) findViewById(R.id.listView1);
    String items[] = { "Fruits", "Vegetables", "Jooses", "Meat", "Toys", "Cookeys" };

    final ListView menu2 = (ListView) findViewById(R.id.listView2);
    final String subitems[] = { "xxx", "xxx", "xxx", "xxx", "xxx", "xxx" };

    menu.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, items));
    menu.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) {

            //Here YourActivity.this means the Context
            menu2.setAdapter(new ArrayAdapter<String>(YourActivity.this,
                    android.R.layout.simple_list_item_1, subitems));
        }
    });

【讨论】：

【解决方案6】：

覆盖您的第一个列表视图（示例中的菜单）onItemClickListener 并根据您的需要准备子项（要在 menu2 中显示的列表）或任何你想显示并调用 notifyDataSetChanged() menu2 适配器（ menu2.getAdapter().notifyDataSetChanged(); ）。

【讨论】：