【问题标题】:Error with showing data from Firebase in Listview在 Listview 中显示来自 Firebase 的数据时出错
【发布时间】:2019-06-22 22:25:46
【问题描述】:

目前,我正在尝试让一个活动在列出类的地方工作,点击后,它会在一个带有 Listview 的单独活动中返回用户的姓名和成绩。当用户注册课程时,他们的 uid 保存在课程下。首先,我正在检索类名下列出的 uid,这很有效。之后,我使用 uid 导航回用户信息并检索名称和等级并将其组合到一个变量中,以便我可以显示它在列表视图中。不幸的是,当我运行应用程序时出现错误:

Can't convert object of type java.lang.String to type com.samuelford48gmail.thsconnect.User

当我在调试模式下运行应用程序时,它说名称和等级为空。此外,当我使用 system.out.println 显示数据快照时,它只返回用户 uid 下的类。我认为部分问题可能是我在 Firebase 中的结构。

这是我的 Firebase 结构:

{
  "Science" : {
    "-LhrSfhNaQX1ZiNToeYQ" : {
  "Students" : {
    "-LhzXqvBPJl-gvN7bZ6c" : "9TKqqNqge5cKpFgjHByAFpZ3iRD2"
  },
  "date_clasname" : "dd",
  "room_number" : "dd",
  "teacher" : "dd",
  "uid" : "-LhrSfhNaQX1ZiNToeYQ"
},
"-LhrSfwx3nKd3DhRNJRp" : {
  "date_clasname" : "dd",
  "room_number" : "dd",
  "teacher" : "dd",
  "uid" : "-LhrSfwx3nKd3DhRNJRp"
},
"-LhrSg-4YJ52a1Zj9LoK" : {
  "Students" : {
    "-LhrfCKXsrjDWC4dJU8H" : "9TKqqNqge5cKpFgjHByAFpZ3iRD2"
  },
  "date_clasname" : "dd",
  "room_number" : "dd",
  "teacher" : "dd",
  "uid" : "-LhrSg-4YJ52a1Zj9LoK"
   }
  },
   "Users" : {
"9TKqqNqge5cKpFgjHByAFpZ3iRD2" : {
  "Classes" : {
    "-LhrfCKVETBZrgOIrCLR" : {
      "date_clasname" : "dd",
      "room_number" : "dd",
      "teacher" : "dd"
    },
    "-LhzWYnqD-qi8v-MFWKF" : {
      "date_clasname" : "dd",
      "room_number" : "dd",
      "teacher" : "dd"
    },
    "-LhzXqv0RZMts7Df1Ehg" : {
      "date_clasname" : "dd",
      "room_number" : "dd",
      "teacher" : "dd"
    }
  },
  "email" : "svhsdev@vigoschools.org",
  "grade" : "11",
  "name" : "Samuel"
},
"NnJlSVeqGXhJ2Nab2bhjr0HIpku2" : {
  "Classes" : {
    "-LhNEZI73xZWbu8tb4ZL" : {
      "date_clasname" : "March 5",
      "room_number" : "101",
      "teacher" : "pence"
    },
    "-LhNFH_LB8PGKKOML-Ta" : {
      "date_clasname" : "d",
      "room_number" : "",
      "teacher" : "s"
    },
    "-LhNFHjC0sYKaXd_OcX2" : {
      "date_clasname" : "d",
      "room_number" : "",
      "teacher" : "s"
    },
    "-LhrbM1htXYd0CxZiKMZ" : {
      "date_clasname" : "dd",
      "room_number" : "dd",
      "teacher" : "dd"

  },
  "email" : "samuelford48@gmail.com",
  "grade" : "12",
  "name" : "Samuel Ford"
},
}
 }
  }

这是使用 Listview 尝试获取用户姓名和成绩的活动的代码:

public class admin_show_students_uid extends AppCompatActivity {

  private FirebaseDatabase database;
  private DatabaseReference myRef;
  String user_info = null;
  String name = null;
ListView lv;
ArrayList<String> list=new ArrayList<>();
@Override
protected void onCreate( Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.admin_show_students_uid);

    lv = (ListView) findViewById(R.id.lv_science_students);
    final ArrayAdapter<String> adapter=new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,list);
    lv.setAdapter(adapter);
    lv.setStackFromBottom(true);
    final String post_key = getIntent().getStringExtra("post_key");
    database = FirebaseDatabase.getInstance();
    myRef = database.getReference("Science").child(post_key).child("Students");
    myRef.addChildEventListener(new ChildEventListener() {
        @Override
        public void onChildAdded(@NonNull DataSnapshot dataSnapshot, String s) {
    //name gets the uid saved
            name = dataSnapshot.getValue(String.class);

      myRef = database.getReference("Users").child(name);

     getusersinfo();        
  adapter.notifyDataSetChanged();
        }

        @Override
        public void onChildChanged(@NonNull DataSnapshot dataSnapshot, @Nullable String s) {

        }

        @Override
        public void onChildRemoved(@NonNull DataSnapshot dataSnapshot) {

        }

        @Override
        public void onChildMoved(@NonNull DataSnapshot dataSnapshot, @Nullable String s) {

        }

        @Override
        public void onCancelled(@NonNull DatabaseError databaseError) {

        }
    });
}

public void getusersinfo(){
    myRef.addListenerForSingleValueEvent(new ValueEventListener() {
  @Override
        public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
            for (DataSnapshot dataSnapshot2 : dataSnapshot.getChildren()) {
                User user = dataSnapshot2.getValue(User.class);
                String name = user.getName();
                String grade = user.getGrade();
             user_info = ("Name " + name + "Grade" + grade);
  list.add(user_info);

            }

        }

        @Override
        public void onCancelled(@NonNull DatabaseError databaseError) {

           }
       });

    }
  }

提前感谢您,如果您对我的代码有任何疑问,请告诉我!

【问题讨论】:

  • 您能否格式化您的数据库架构或至少提供一个屏幕截图?

标签: java android firebase listview firebase-realtime-database


【解决方案1】:

问题是您获得了对特定用户的引用,但在 getuserinfo() 中您正在迭代其属性。相反,只需从dataSnapshot 获取User。见:

public void getusersinfo(){
    studentRef.addListenerForSingleValueEvent(new ValueEventListener() {
        @Override
        public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
            User user = dataSnapshot.getValue(User.class);
            String email = user.getName();
            String grade = user.getGrade();
            user_info = ("Name " + email + "Grade" + grade);
            list.add(user_info);               
        }

        @Override
        public void onCancelled(@NonNull DatabaseError databaseError) {

        }
    });
}

【讨论】:

  • 那行不通,也没有任何意义。 getusersinfo方法的重点是返回各自uid的名称和等级,然后添加到listview的数组中。
  • 抱歉,有误会。发现问题并更新了我的答案@Samuel
  • 谢谢...成功返回 user_info 但由于某种原因数组大小一直返回 0,所以我的列表视图为空白。
  • 您应该在onDataChanged 方法中更新您的ListView。因为 Firebase 的 ValueEventListener 异步工作 @Samuel
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