【发布时间】:2019-05-04 08:50:06
【问题描述】:
这是我目前所写的:
int main(void) {
int playerJerseys[5];
int playerRatings[5];
printf("Enter player 1's jersey number:\n");
scanf("%d",&playerJerseys[0]);
printf("Enter player 1's rating:\n\n");
scanf("%d",&playerRatings[0]);
printf("Enter player 2's jersey number:\n");
scanf("%d",&playerJerseys[1]);
printf("Enter player 2's rating:\n\n");
scanf("%d",&playerRatings[1]);
printf("Enter player 3's jersey number:\n");
scanf("%d",&playerJerseys[2]);
printf("Enter player 3's rating:\n\n");
scanf("%d",&playerRatings[2]);
printf("Enter player 4's jersey number:\n");
scanf("%d",&playerJerseys[3]);
printf("Enter player 4's rating:\n\n");
scanf("%d",&playerRatings[3]);
printf("Enter player 5's jersey number:\n");
scanf("%d",&playerJerseys[4]);
printf("Enter player 5's rating:\n\n");
scanf("%d",&playerRatings[4]);
printf("ROSTER\n");
printf("Player 1 -- Jersey number: %d, Rating: %d\n",playerJerseys[0],playerRatings[0]);
printf("Player 2 -- Jersey number: %d, Rating: %d\n",playerJerseys[1],playerRatings[1]);
printf("Player 3 -- Jersey number: %d, Rating: %d\n",playerJerseys[2],playerRatings[2]);
printf("Player 4 -- Jersey number: %d, Rating: %d\n",playerJerseys[3],playerRatings[3]);
printf("Player 5 -- Jersey number: %d, Rating: %d\n\n",playerJerseys[4],playerRatings[4]);
char selection;
printf("MENU\n");
printf("u - Update player rating\n");
printf("a - Output players above a rating\n");
printf("r - Replace player\n");
printf("o - Output roster\n");
printf("q - Quit\n\n");
printf("Choose an option:\n");
scanf("%c",&selection);
if(selection == 'q'){
return 0;
}
else if(selection == 'u'){
int userJersey;
int userRating;
printf("Enter a jersey number:\n");
scanf("%d",&userJersey);
for(int i = 0; i < 5; ++i){
if(playerJerseys[i] == userJersey){
printf("Enter a new rating for player:\n");
scanf("%d",&userRating);
playerRatings[i] = userRating;
}
}
}
else if(selection == 'o'){
printf("ROSTER\n");
printf("Player 1 -- Jersey number: %d, Rating: %d\n",playerJerseys[0],playerRatings[0]);
printf("Player 2 -- Jersey number: %d, Rating: %d\n",playerJerseys[1],playerRatings[1]);
printf("Player 3 -- Jersey number: %d, Rating: %d\n",playerJerseys[2],playerRatings[2]);
printf("Player 4 -- Jersey number: %d, Rating: %d\n",playerJerseys[3],playerRatings[3]);
printf("Player 5 -- Jersey number: %d, Rating: %d\n\n",playerJerseys[4],playerRatings[4]);
}
return 0;
}
当提供此输入时:
84 7
23 4
4 5
30 2
66 9
u
4
6
o
q
这是输出:
Player 1 -- Jersey number: 84, Rating: 7
Player 2 -- Jersey number: 23, Rating: 4
Player 3 -- Jersey number: 4, Rating: 5
Player 4 -- Jersey number: 30, Rating: 2
Player 5 -- Jersey number: 66, Rating: 9
MENU
u - Update player rating
a - Output players above a rating
r - Replace player
o - Output roster
q - Quit
Choose an option:
想要的输出是:
ROSTER
Player 1 -- Jersey number: 84, Rating: 7
Player 2 -- Jersey number: 23, Rating: 4
Player 3 -- Jersey number: 4, Rating: 6
Player 4 -- Jersey number: 30, Rating: 2
Player 5 -- Jersey number: 66, Rating: 9
MENU
u - Update player rating
a - Output players above a rating
r - Replace player
o - Output roster
q - Quit
Choose an option:
当提供 u 作为输入时,后续数字应该会更改其中一名玩家的评分,但对我来说它不起作用。我不确定我是否只是不知道如何比较字符?还是我的 if 语句和 else-if 语句设置不正确?任何建议表示赞赏。
【问题讨论】:
-
请尝试重新表述您的问题,以包含 minimum 工作示例。那里有很多不必要的代码。尝试将其简化为字符比较。
-
我看不出输出有什么不同,对吗?您是否还在调试器中逐行运行代码,检查变量并查看发生了什么?
-
更新播放等级后程序退出。我没有看到“菜单”上有任何循环。 “这是输出”如何显示?
-
OT:当调用任何
scanf()系列函数时,始终检查返回值(而不是参数值)以确保操作成功 -
关于:
scanf("%c",&selection);你在哪里允许 '\n' 被吸收/跳过 建议:if( scanf(" %c",&selection) != 1) { fprintf( stderr, "failed to input menu selection\n" );注意%c前面的空间,所以任何“空白”都会被消耗掉
标签: c if-statement char