【发布时间】:2012-01-29 13:05:08
【问题描述】:
我正在尝试使用 SimpleAdapter 和 TableView 显示我的 SQLite 表的内容。 它在第一次启动时工作得很好,但是当我重新启动 Activity 时,它会在 listView 中再次添加表。 每次我从前面的菜单启动意图时都会发生这种情况。
在我看来,SimpleAdapter 是上次存储的,并在从菜单中打开 Intent 时再次添加?
也许有办法在每次启动适配器时重置它?
我是编程新手,希望有人可以帮助我:)
一些代码:
static final ArrayList<HashMap<String,String>> results = new ArrayList<HashMap<String,String>>();
private String tableName = DBAdapter.tableName;
private SQLiteDatabase newDB;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
openAndQueryDatabase();
displayResultList();
}
private void displayResultList() {
ListAdapter adapter = new SimpleAdapter(
this,
results,
R.layout.liste,
new String[] {"Name","LastName","Age"},
new int[] {R.id.item_id,R.id.item_name,R.id.item_tid}
);
setListAdapter(adapter);
}
private void openAndQueryDatabase() {
try {
DBAdapter dbHelper = new DBAdapter(this.getApplicationContext());
newDB = dbHelper.getWritableDatabase();
Cursor c = newDB.rawQuery("SELECT Startnr, Navn, Tid FROM " +
tableName + " ORDER BY Startnr ASC" , null);
if (c != null ) {
if (c.moveToFirst()) {
do {
HashMap<String,String> list = new HashMap<String,String>();
String firstName = c.getString(c.getColumnIndex("Startnr"));
String lastName = c.getString(c.getColumnIndex("Navn"));
String age = c.getString(c.getColumnIndex("Tid"));
list.put("Name", "" + firstName);
list.put("LastName", "" + lastName);
list.put("Age", "" + age);
results.add(list);
}while (c.moveToNext());
}
}
} catch (SQLiteException se ) {
Log.e(getClass().getSimpleName(), "Could not create or Open the database");
} finally {
if (newDB != null)
newDB.close();
}
}
【问题讨论】:
-
对我来说看起来不错,因为您在 onCreate 中填写您的列表,每个活动只调用一次。您是否在任何其他生命周期方法(如 onResume)中有代码?
标签: android sqlite listview listadapter simpleadapter