【发布时间】:2014-12-26 23:24:02
【问题描述】:
我正在制作一个程序,允许用户在屏幕上绘制多个形状并选择所需的颜色。目前,我有九种预设颜色可供用户选择。我计划使用JColorChooser 来允许用户选择不同的颜色。但是,我无法找到一种方法来存储可以选择的额外颜色,以便在重新绘制绘制的形状时,它们将保持与绘制时相同的颜色。
我想出了一种方法,可以按照绘制的顺序和绘制时使用的颜色重新绘制形状,如下所示:
private List<Shape> shapeList = new ArrayList<Shape>();
private List<Integer> opNumList = new ArrayList<Integer>();
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
int index = 0;
Graphics2D g2 = (Graphics2D) g.create();
if (!opNumList.isEmpty()) {
for (Shape s : shapeList) {
switch (opNumList.get(index))
case 0: g2.setColor(Color.red); g2.draw(s); break;
case 1: g2.setColor(Color.red); g2.fill(s); break;
case 2: g2.setColor(Color.orange); g2.draw(s); break;
case 3: g2.setColor(Color.orange); g2.fill(s); break;
case 4: g2.setColor(Color.yellow); g2.draw(s); break;
case 5: g2.setColor(Color.yellow); g2.fill(s); break;
case 6: g2.setColor(Color.green); g2.draw(s); break;
case 7: g2.setColor(Color.green); g2.fill(s); break;
case 8: g2.setColor(Color.blue); g2.draw(s); break;
case 9: g2.setColor(Color.blue); g2.fill(s); break;
case 10: g2.setColor(purple); g2.draw(s); break;
case 11: g2.setColor(purple); g2.fill(s); break;
case 12: g2.setColor(brown); g2.draw(s); break;
case 13: g2.setColor(brown); g2.fill(s); break;
case 14: g2.setColor(Color.white); g2.draw(s); break;
case 15: g2.setColor(Color.white); g2.fill(s); break;
case 16: g2.setColor(Color.black); g2.draw(s); break;
case 17: g2.setColor(Color.black); g2.fill(s); break;
default: return;
}
index++;
}
}
}
@Override
public void mouseReleased(MouseEvent ev) {
if (color == Color.red) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(0);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(1);
}
if (color == Color.orange) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(2);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(3);
}
if (color == Color.yellow) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(4);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(5);
}
if (color == Color.green) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(6);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(7);
}
if (color == Color.blue) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(8);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(9);
}
if (color == purple) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(10);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(11);
}
if (color == brown) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(12);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(13);
}
if (color == Color.white) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(14);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(15);
}
if (color == Color.black) {
if (toolNum == LINE || (toolNum == RECTANGLE && !cbFillItem.isSelected()) || (toolNum == OVAL && !cbFillItem.isSelected()))
opNumList.add(16);
if ((toolNum == RECTANGLE || toolNum == OVAL) && cbFillItem.isSelected())
opNumList.add(17);
}
repaint();
}
所以发生的情况是,当用户绘制一个形状时,它存储在ArrayList 的Shape 对象中。根据绘制的形状及其颜色,整数存储在单独的列表中。然后当程序重绘所有形状时,它会遍历列表中的每个形状,并为形状赋予它们绘制时使用的颜色,并在必要时填充它们。
现在,我想弄清楚的是一种将这些颜色转移到它们自己的 List 甚至是 Map 的方法,以避免创建大量 Color 对象并添加到已经长长的代码列表,这样如果用户决定使用其他颜色,程序就会知道什么颜色属于什么形状。例如,如果用户决定绘制一个颜色为 128,128,128 的填充矩形;当程序重绘形状时,它将知道矩形已被填充并被着色为特定的灰色阴影。但我还没有走那么远。现在,我正在尝试找到一种仅适用于我目前拥有的九种颜色的解决方案。
有没有人知道如何做到这一点?
【问题讨论】: