【发布时间】:2017-09-17 15:12:21
【问题描述】:
我有一个片段活动。我在它上面实现了一个搜索视图,它的项目是从作为列表视图列出的 firebase 加载的。当我等待一段时间并加载数据时它会起作用。但是,当我在加载发生之前立即单击 searchview 时,即使经过很长时间也没有加载任何数据。然后当我回到主片段并再次返回时立即加载数据。我认为这是一个小问题,但是我是android开发的初学者,所以对我来说很难。这是我的代码:
public class FragmentHome extends Fragment {
private SearchView search;
View view;
DatabaseReference dataRef;
private FirebaseListAdapter<String> firebaseListAdapter;
ListView mListView;
private TextView text;
ArrayList<String> city=new ArrayList<String>();
private int i=0;
private String data,val,var;
ArrayAdapter<String> adapter;
@Nullable
@Override
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable final Bundle savedInstanceState) {
View v= inflater.inflate(R.layout.activity_fragment_home,container,false);
if (container!=null){
container.removeAllViews();
}
search= (SearchView) v.findViewById(R.id.search);
search.onActionViewExpanded();
search.setIconified(false);
search.setQueryHint("Search Docter By City Or Department");
mListView= (ListView) v.findViewById(R.id.mList);
mListView.setVisibility(View.INVISIBLE);
dataRef=FirebaseDatabase.getInstance().getReference().child("Docters");
adapter=new ArrayAdapter<String>(getActivity(), android.R.layout.simple_list_item_1, city);
mListView.setAdapter(adapter);
dataRef.addChildEventListener(new ChildEventListener() {
@Override
public void onChildAdded(DataSnapshot dataSnapshot, String s) {
data=dataSnapshot.child("city").getValue(String.class);
val=dataSnapshot.child("department").getValue(String.class);
if (!city.contains(data)){
city.add(data);
}
if (!city.contains(val)){
city.add(val);
}
adapter.notifyDataSetChanged();
}
@Override
public void onChildChanged(DataSnapshot dataSnapshot, String s) {
data=dataSnapshot.child("city").getValue(String.class);
val=dataSnapshot.child("department").getValue(String.class);
city.add(data);
city.add(val);
city.add(var);
adapter.notifyDataSetChanged();
}
@Override
public void onChildRemoved(DataSnapshot dataSnapshot) {
}
@Override
public void onChildMoved(DataSnapshot dataSnapshot, String s) {
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
search.setOnQueryTextListener(new SearchView.OnQueryTextListener() {
@Override
public boolean onQueryTextSubmit(String text) {
return false;
}
@Override
public boolean onQueryTextChange(String text) {
if (!text.isEmpty()){
mListView.setVisibility(View.VISIBLE);
adapter.getFilter().filter(text);
}else{
mListView.setVisibility(View.INVISIBLE);
}
return false;
}
});
mListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
String itemRef = (String) adapter.getItem(position);
search.setVisibility(View.INVISIBLE);
mListView.setVisibility(View.INVISIBLE);
FragmentTransaction ft=getChildFragmentManager().beginTransaction();
DocterList fragment=new DocterList();
Bundle item=new Bundle();
item.putString("item",itemRef);
fragment.setArguments(item);
ft.replace(R.id.activity_fragment_home,fragment);
ft.addToBackStack(null);
ft.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_FADE);
ft.commit();
}
});
return v;
}}
如果有人知道如何解决这个问题,请帮助我。提前谢谢...
【问题讨论】:
标签: android listview android-fragments firebase searchview