【发布时间】:2016-03-16 06:38:45
【问题描述】:
我已经使用自定义列表视图,使用适配器类中的适配器类在一个 ROW 中的两个复选框为此,我需要选择一个复选框,无论是 Checkbox1 Row/Column 与 Checkbox 2 相同。 例如,我在 Listview 中有 5 行 Totally 10 Checkbox inside Listview Out 10 一次只有一个选择,所有其他都应该取消选择
关于我尝试了 Lot 但仅选择 Checkbox1 列的任何想法 请帮忙
public class ListViewAdapter extends ArrayAdapter<Friend> {
private List<Friend> myFriends;
private Activity activity;
private int selectedPosition = -1;
String flag="";
String[]ids=new String[100];
String[]ids1=new String[100];
public ListViewAdapter(Activity context, int resource, List<Friend> objects) {
super(context, resource, objects);
this.activity = context;
this.myFriends = objects;
}
@Override
public View getView(final int position, View convertView, ViewGroup parent) {
final ViewHolder holder;
LayoutInflater inflater = (LayoutInflater) activity.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);
// If holder not exist then locate all view from UI file.
if (convertView == null) {
// inflate UI from XML file
convertView = inflater.inflate(R.layout.item_listview, parent, false);
// get all UI view
holder = new ViewHolder(convertView);
// set tag for holder
convertView.setTag(holder);
} else {
// if holder created, get tag from view
holder = (ViewHolder) convertView.getTag();
}
holder.checkBox.setTag(position); // This line is important.
holder.checkBox1.setTag(position + 100);
holder.friendName.setText(getItem(position).getName());
holder.rdgrp.setTag(position);
ids[position]=holder.checkBox.getTag().toString();
ids1[position]=holder.rdgrp.getTag().toString();
// System.out.println("praveen"+ids[position]);
if (position == selectedPosition) {
holder.rdgrp.setActivated(true);
} else holder.rdgrp.setActivated(false);
if( holder.checkBox.getTag().equles(position)){
holder.checkBox.setOnClickListener(onStateChangedListener(holder.checkBox, position));
}else{
holder.checkBox1.setOnClickListener(onStateChangedListener(holder.checkBox1, position));
}
return convertView;
}
public View.OnClickListener onStateChangedListener(final RadioGroup gry, final int position ){
return new View.OnClickListener() {
@Override
public void onClick(View v) {
if (gry.isClickable()) {
selectedPosition = position;
} else {
selectedPosition = -1;
}
notifyDataSetChanged();
}
};
}
private static class ViewHolder {
private TextView friendName;
private CheckBox checkBox,checkBox1;
public ViewHolder(View v) {
checkBox = (CheckBox) v.findViewById(R.id.check);
checkBox1 = (CheckBox) v.findViewById(R.id.check1);
friendName = (TextView) v.findViewById(R.id.name);
}
}
}
【问题讨论】:
-
你尝试了什么?
-
你能发布你的代码吗?
-
是的,我刚刚在问题下方发布了我的代码
-
你能帮帮我吗
标签: android android-layout listview android-fragments android-intent