如何随机调用函数unity c# [重复]

Question

我正在制作一个无尽的汽车驾驶游戏，我想在玩家汽车靠近一辆敌车时随机调用其中一个 switchLane 函数。关键是当你靠近时让其他一些汽车切换到随机车道。我正在寻找的主要内容是每次靠近时随机调用这 4 个 switchLane 函数之一的方法。

public class EnemyScript : MonoBehaviour
{
 public float speed;
 private GameObject playerTransform;
 private GameObject enemyCarPrefab;
 private float distanceToNextCar;
 public float distance;

 private float roadWidth;
 private float lane1 = 7.25f;
 private float lane2 = 2.45f;
 private float lane3 = 2.4f;
 private float lane4 = 7.3f;

 // Start is called before the first frame update
 void Start()
 {
    
 }

 // Update is called once per frame
 void Update()
 {
     playerTransform = GameObject.FindGameObjectWithTag("Player");
     enemyCarPrefab = GameObject.FindGameObjectWithTag("BaseCar");

     distanceToNextCar = enemyCarPrefab.transform.position.z - distance;
     if (playerTransform.transform.position.z > distanceToNextCar)
     {
         switchLane1();
         switchLane2();
         switchLane3();
         switchLane4();
     }
 }


 private void switchLane1()
 {
     Vector3 targetPos1 = new Vector3(-lane1, 0, 0);
     transform.position += (targetPos1 * speed * Time.deltaTime);



     if (transform.position.x <= -lane1)
     {
         Vector3 newPositionLeft = new Vector3(-lane1, transform.position.y, transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane1)
     {
         Vector3 newPositionRight = new Vector3(lane1, transform.position.y, transform.position.z);
         transform.position = newPositionRight;
     }

 }

 private void switchLane2()
 {
     Vector3 targetPos2 = new Vector3(-lane2, 0, 0);
     transform.position += (targetPos2 * speed * Time.deltaTime);



     if (transform.position.x <= -lane2)
     {
         Vector3 newPositionLeft = new Vector3(-lane2, transform.position.y, transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane2)
     {
         Vector3 newPositionRight = new Vector3(lane2, transform.position.y, transform.position.z);
         transform.position = newPositionRight;
     }

 }

 private void switchLane3()
 {
     Vector3 targetPos3 = new Vector3(lane3, 0, 0);
     transform.position += (targetPos3 * speed * Time.deltaTime);



     if (transform.position.x <= -lane3)
     {
         Vector3 newPositionLeft = new Vector3(-lane3, transform.position.y, transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane3)
     {
         Vector3 newPositionRight = new Vector3(lane3, transform.position.y, transform.position.z);
         transform.position = newPositionRight;
     }

 }

 private void switchLane4()
 {
     Vector3 targetPos4 = new Vector3(lane4, 0, 0);
     transform.position += (targetPos4 * speed * Time.deltaTime);



     if (transform.position.x <= -lane4)
     {
         Vector3 newPositionLeft = new Vector3(-lane4, transform.position.y, transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane4)
     {
         Vector3 newPositionRight = new Vector3(lane4, transform.position.y, transform.position.z);
         transform.position = newPositionRight;
     }

 }
}

Answer 1

例如呢

// for more flexibility rather use an array
// You should also add the ability to change it via the Inspector
[SerializeField]
private float[] lanes = new []
{
    7.25f,
    2.45f,
    2.4f,
    7.3f
};

// pass the index of the lane to your method
// this way you can handle all lanes with a single method
private void SwitchToLane(int index)
{
    Debug.Log($"Switching to lane {index}", this);

    // Get the float at given index in lanes
    var x = lanes[index];

    var targetPos = new Vector3(x, 0, 0);
    transform.position += (targetPos * speed * Time.deltaTime);

    if (transform.position.x <= -x)
    {
       var newPositionLeft = new Vector3(-x, transform.position.y, transform.position.z);
       transform.position = newPositionLeft;
    }
    // Rather use 'else if' when it is already clear that only one case can be true at the same time
    else if (transform.position.x >= x)
    {
       var newPositionRight = new Vector3(x, transform.position.y, transform.position.z);
       transform.position = newPositionRight;
    }
}

然后调用

// Call this to switch to any random lane
private void SwitchToRandomLane()
{
    // generate a random int between 0 and lanes.Length - 1
    // second parameter is EXCLUSIVE!
    var random = Random.Range(0, lanes.Length); 

    SwitchToLane(random);
}
        

---

补充说明：

1. 您还需要以某种方式更改Update 中的条件检查。目前，一旦玩家低于距离阈值一次，您每帧都会切换车道！

2. 您可能希望在某处存储当前车道索引，因此当调用 SwitchToRandomLane 时，当前索引将被排除在选项之外，您只能绝对切换到与您已经在的车道不同的车道。

这两点我留给你。

Answer 2

你可以做一个随机数

int randomNum = Random.Range(0, 4);

并在具有四个功能的switch 上使用它，就像这样

switch(randomNum){
case 0:
  switchLane1();
break;
case 1:
  switchLane2();
break;
case 2:
  switchLane3();
break;
case 3:
  switchLane4();
break;
}

但是我相信有更好的解决方案，我看到这么多重复的代码，也许你可以为四种情况制作一个带有参数的函数，然后简单地发送一个带有方向或数字的参数。