【发布时间】:2021-03-02 21:35:42
【问题描述】:
我遇到了一个小问题 - 我正在尝试在控制台应用中将 random 乘以 int。我有一个错误:
运算符“*”不能应用于“随机”和“整数”类型的操作数
我已经尝试过:rndAttackPoints = attackPoints 然后
这个int damagePoints = (rndAttackPoints * strenghtPoints1) - defencePoints1;进入
这个int damagePoints = (attackPoints * strenghtPoints1) - defencePoints1; 但这不起作用。
所以我问你,你知道如何在 C# 中将 Random 乘以 int 吗?
//Elf
int healthPoints1 = 100;
int defencePoints1 = 3;
int strenghtPoints1 = 2;
// Goblin
int healthPoints2 = 100;
int defencePoints2 = 5;
int strenghtPoints2 = 1;
Random rndAttackPoints = new Random();
Console.WriteLine($"You've attacked: {rndAttackPoints.Next(5, 10)} HP");
int damagePoints = (rndAttackPoints * strenghtPoints1) - defencePoints1;
【问题讨论】:
-
提示:您通过
rndAttackPoints.Next(5, 10)获得随机值,而不是通过将rndAttackPoints转换为int。 -
new Random()是可以生成随机事物的东西。rndAttackPoints.Next(5, 10)是获取您正在寻找的随机值的方法。存储结果。
标签: c# random console console-application multiplication