【发布时间】：2015-11-23 17:01:42
【问题描述】：
我在活动 A 中有两个 Spinners，它们持有以下物品：{"Pro-XXX-XXX","TRN-XXX-XXX","SRV-XXX-XXX","PRO-REE-BERGARDING","PRO-SKM-SSS","PRO-SKM-DI","PRO-SKM-PACKING","PRO-SIE-AVAGO_S110","PRO-SIE-BIOCON","PRO-BCM-T13/T17"}。
假设在 Spinner1 中选择值 SRV，在 Spinner2 中选择 TRN。最后，我将选定的值保存到 SQLite 中。
在活动 B 中，我想检索项目并显示在 SpinnerA 和 B 上。请注意，Spinner A 和 B 与活动 A 中的 Spinner 具有相同的项目。
活动 B
public class B extends Fragment {
SQLiteDatabase database;
MyDatabaseHelper dbHelper;
Cursor c;
Spinner weather3,status3,project1,project2,project3,project4;
EditText name3;
EditText date3;
String date;
String ID;
String Project11;
String Project22;
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
// TODO Auto-generated method stub
View view = inflater.inflate(R.layout.u, container, false);
dbHelper = new MyDatabaseHelper(getActivity());
project1 = (Spinner) view.findViewById(R.id.spinner8);
project2 = (Spinner) view.findViewById(R.id.spinner9);
name3 = (EditText)view. findViewById(R.id.editText9);
date3 = (EditText)view. findViewById(R.id.editText12);
Bundle bundle=this.getArguments();
if(getArguments()!=null)
{
date=bundle.getString("date1");
ID = bundle.getString("ID");
}
Log.e("TAG",date);
Log.e("TAG",ID);
RetrievePage(date, ID);
return view;
}
public void addProject1(String l)
{
String[] arr = new String[]{"Pro-XXX-XXX","TRN-XXX-XXX","SRV-XXX-XXX","PRO-REE-BERGARDING","PRO-SKM-SSS","PRO-SKM-DI","PRO-SKM-PACKING","PRO-SIE-AVAGO_S110",
"PRO-SIE-BIOCON","PRO-BCM-T13/T17","TRIN-IN_HOUSE","TRIN-EXTERNAL","SRIV-SIE-LEMONGRASS","SRV-PW-SIMOCODE","SRV-REE-SIMOCODE","PRO-SKM-D5","PRO-SKM-DRIOU","PRO-BKI-DESMET",
"PRO-BKI-INFINEON","PRO-INH-ANDROID","PRO-BCM-S120","PRO-GAW-OP"};
List<String> list = new ArrayList<String>();
String project11 = l;
list.add(project11);
for(String s:arr){
if(!list.contains(s)){
list.add(s);
}
}
ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_spinner_dropdown_item, list);
adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
project1.setAdapter(adapter);
}
public void addProject2(String d)
{
String[] arr = new String[]{"Pro-XXX-XXX","TRN-XXX-XXX","SRV-XXX-XXX","PRO-REE-BERGARDING","PRO-SKM-SSS","PRO-SKM-DI","PRO-SKM-PACKING","PRO-SIE-AVAGO_S110",
"PRO-SIE-BIOCON","PRO-BCM-T13/T17","TRIN-IN_HOUSE","TRIN-EXTERNAL","SRIV-SIE-LEMONGRASS","SRV-PW-SIMOCODE","SRV-REE-SIMOCODE","PRO-SKM-D5","PRO-SKM-DRIOU","PRO-BKI-DESMET",
"PRO-BKI-INFINEON","PRO-INH-ANDROID","PRO-BCM-S120","PRO-GAW-OP"};
List<String> list = new ArrayList<String>();
String project22 = d;
list.add(project22);
for(String s:arr){
if(!list.contains(s)){
list.add(s);
}
}
ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_spinner_dropdown_item, list);
adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
project2.setAdapter(adapter);
}
public void RetrievePage(String date, String id) {
final String date2=date;
final String id2 = id;
database = dbHelper.getWritableDatabase();
c = database.rawQuery("SELECT i.Weather, i.Status,w.Subcontractors, w.NumberOfPerson, w.NumberOfHours, wd.Project, wd.WorkDescription, wd.Per, wd.TimeIn, wd.TimeOut FROM Information i LEFT JOIN WorkForce w ON w.TInfo_id = i._id LEFT JOIN WorkDetails wd ON wd.Twf_id=w._id WHERE i.Name = ? AND i._id= ? ",
new String[]{String.valueOf("Lim Chun Yao"),String.valueOf(id2)}, null);
if (c != null) {
while (c.moveToNext()) {
Details WD = new Details();
Project11=c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
Project22=c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
addProject1(Project11);
addProject2(Project22);
WD.setProject(Project11);
WD.setProject(Project22);
}
Log.e("TAG1",Project11);
Log.e("TAG2",Project22);
c.close();
}
}
}
SQLite 中插入的值正确，但 Spinner A 上显示的值不正确。
日志显示
11-23 16:46:29.517 29621-29621/? E/TAG1﹕ TRN-XXX-XXX
11-23 16:46:29.517 29621-29621/? E/TAG2﹕ TRN-XXX-XXX
微调器 A 和 B 也显示 TRN。
但是 Spinner A 应该显示 SRV 而不是 TRN。
我知道有一个方法叫setSelection()，但它如何应用于我的案例？
已编辑
public void RetrievePage(String date, String id) {
final String date2 = date;
final String id2 = id;
database = dbHelper.getWritableDatabase();
c = database.rawQuery("SELECT i.Weather, i.Status,w.Subcontractors, w.NumberOfPerson, w.NumberOfHours, wd.Project, wd.WorkDescription, wd.Per, wd.TimeIn, wd.TimeOut FROM Information i LEFT JOIN WorkForce w ON w.TInfo_id = i._id LEFT JOIN WorkDetails wd ON wd.Twf_id=w._id WHERE i.Name = ? AND i._id= ? ",
new String[]{String.valueOf("Lim Chun Yao"), String.valueOf(id2)}, null);
int rowNum = 1;
if (c != null) {
while (c.moveToNext()) {
Details WD = new Details();
switch (rowNum) {
case 1:
Project11 = c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
addProject1(Project11);
WD.setProject(Project11);
break;
case 2:
Project22 = c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
addProject2(Project22);
WD.setProject(Project22);
break;
case 3:
Project33 = c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
addProject3(Project33);
WD.setProject(Project33);
break;
case 4:
Project44 = c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
addProject4(Project44);
WD.setProject(Project44);
break;
}
rowNum += 1;
}
c.close();
Log.e("TAG1", Project11);
Log.e("TAG2", Project22);
}
}
}
现在微调器已经可以显示插入到第一个的值。但是如果spinner Activity A中没有插入值，如何使微调器显示Pro-XXX-XXX？
【问题讨论】：
-
你可以从数据库中获取值，并构建一个方法来搜索你的数组中的值，获取数组中的索引，然后使用 spinner 方法设置他的索引。这可以帮助你：stackoverflow.com/questions/2390102/…
标签： android sqlite android-sqlite spinner android-spinner