【问题标题】:Capture image using dynamic co-ordinates through the camera通过相机使用动态坐标捕捉图像
【发布时间】:2018-02-06 12:04:54
【问题描述】:

我正在制作一个基于相机的应用程序,我在相机上放置了一个矩形视图。 当我使用new Camera.PictureCallback() 捕获图像时,我裁剪了该图像,以便获得矩形的一部分。 嗯,它工作正常。

现在我实现了View.OnTouchListener 并使用它使形状可移动。

因此,我需要使用用户的最终选择来捕获图像,例如他们放置矩形的位置。

Bitmap imageOriginal = BitmapFactory.decodeByteArray(data, 0, data.length); // 2560×1440
                float scale = 1280 / 1000;
                int left = (int) (scale * (imageOriginal.getWidth() - 250) / 2);
                int top = (int) (scale * (imageOriginal.getHeight() - 616) / 2);
                int width = (int) (scale * 750);
                int height = (int) (scale * 616);
                Bitmap imageConverted = Bitmap.createBitmap(imageOriginal, left, top, width, height, null, false);

这是我用来裁剪图像的方法。这些值是硬线来找到确切位置的。 现在我需要改变矩形的顶部、底部、高度、宽度的值。

//我用来绘制那个矩形的customView

public class CustomView extends View  {
    private Paint paint = new Paint();
    public CustomView(Context context) {
        super(context);
    }

    @Override
    protected void onDraw(Canvas canvas) { // Override the onDraw() Method
        super.onDraw(canvas);

        paint.setStyle(Paint.Style.STROKE);
        paint.setColor(Color.GREEN);
        paint.setStrokeWidth(10);

        //center
        int x0 = canvas.getWidth()/2;
        int y0 = canvas.getHeight()/2;
        int dx = canvas.getHeight()/3;
        int dy = canvas.getHeight()/3;
        //draw guide box
        canvas.drawRect(x0-dx, y0-dy, x0+dx, y0+dy, paint);
    }


}

//我的图片回调代码

  Camera.PictureCallback mPicture = new Camera.PictureCallback() {

        public void onPictureTaken(byte[] data, Camera camera) {

            // Replacing the button after a photho was taken.


            // File name of the image that we just took.
            fileName = "IMG_" + new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date()).toString() + ".jpg";

            // Creating the directory where to save the image. Sadly in older
            // version of Android we can not get the Media catalog name
            File mkDir = new File(sdRoot, dir);
            mkDir.mkdirs();

            // Main file where to save the data that we recive from the camera
            File pictureFile = new File(sdRoot, dir + fileName);

            // Cropping image with the corresponding co-ordinates and save in to a file
            try {

                Bitmap imageOriginal = BitmapFactory.decodeByteArray(data, 0, data.length); // 2560×1440
                float scale = 1280 / 1000;
                int left = (int) (scale * (imageOriginal.getWidth() - 250) / 2);
                int top = (int) (scale * (imageOriginal.getHeight() - 616) / 2);
                int width = (int) (scale * 750);
                int height = (int) (scale * 616);
                Bitmap imageConverted = Bitmap.createBitmap(imageOriginal, left, top, width, height, null, false);

                FileOutputStream purge = new FileOutputStream(pictureFile);
                imageConverted.compress(Bitmap.CompressFormat.JPEG, 100, purge);
                purge.flush();
                purge.close();

            } catch (FileNotFoundException e) {
                Log.d("DG_DEBUG", "File not found: " + e.getMessage());
            } catch (IOException e) {
                Log.d("DG_DEBUG", "Error accessing file: " + e.getMessage());
            }

            // Adding Exif data for the orientation.
            try {
                ProjectManager.getInstance().settings.IMAGE_LOCATION = "/sdcard/" + dir + fileName;
                exif = new ExifInterface(ProjectManager.getInstance().settings.IMAGE_LOCATION);
                exif.setAttribute(ExifInterface.TAG_ORIENTATION, "" + orientation);
                exif.saveAttributes();
                mView.saveImage(dir + fileName);
            } catch (IOException e) {
                e.printStackTrace();
            }

        }
    };

【问题讨论】:

  • 用户在哪里放置绿色矩形,我只需要捕获或保存该部分。
  • 绿色矩形位于相机视图上方。那个背景是一个正在运行的相机。
  • 没有回复??为什么??
  • 嗨@Varun Chandran .. 到目前为止你有没有找到任何解决方案?
  • @VibhorBhardwaj 下面的答案给出了类似的输出,但对我的问题并不完美。

标签: android dynamic view android-camera android-canvas


【解决方案1】:

对我来说,我拍了一张图像,然后根据图像所选区域的尺寸进行裁剪..

public void onPictureTaken(byte[] data, Camera camera) {


                Bitmap imageOriginal = BitmapFactory.decodeByteArray(data, 0, data.length, null);
                int width = imageOriginal.getWidth();
                int height = imageOriginal.getHeight(); // for width
                int narrowSize = Math.min(width, height); // for height
                int differ = (int) Math.abs((imageOriginal.getHeight() - imageOriginal.getWidth()) / 2.0f);  // for dimension
                width = (width == narrowSize) ? 0 : differ;
                height = (width == 0) ? differ : 0; 

                Matrix rotationMatrix = new Matrix();
                rotationMatrix.postRotate(90); // for orientation

                Bitmap imageCropped = Bitmap.createBitmap(imageOriginal, width, height, narrowSize, narrowSize, rotationMatrix, false);


    }

Capture Image

Output Image

【讨论】:

    【解决方案2】:

    如果我理解,您的矩形是 mCustomView.getWidth()*2/3 像素宽,mCustomView.getHeight()*2/3 像素高,它的左角是 mCustomView.getWidth() 的 1/6您的帖子正确。

    public void onPictureTaken(byte[] data, Camera camera) {
        //.../
        Bitmap imageOriginal = BitmapFactory.decodeByteArray(data, 0, data.length);
        int[] customViewPosition;
        mCustomView.getLocationInWindow(customViewPosition);
        int[] surfacePosition;
        mSurfaceView.getLocationInWindow(surfacePosition);
    
        float scale = imageOriginal.getWidth()/(float)mSurfaceView.getWidth();
        int left = (int) scale*(customViewPosition[0] + mCustomView.getWidth()/6F - surfacePosition[0]);
        int top = (int) scale*(customViewPosition[1] + mCustomView.getHeight()/6F - surfacePosition[1]);
        int width = (int) scale*mCustomView.getWidth()*2/3;
        int height = (int) scale*mCustomView.getHeight()*2/3;
        Bitmap imageCropped = Bitmap.createBitmap(imageOriginal, left, top, width, height, null, false);
        //.../
    }
    

    【讨论】:

    • 嗨,我试过了,但是 customViewPosition,surfacePosition 总是给出 0,0??
    • 我有疑问? surfaceview 将始终保持不变,对吗?只有customview会改变吗?
    • customViewPosition 和 surfacePosition 可以是 (0,0)。但这取决于您的布局。 mCustomView 也很可能保持不变。如果我必须经常使用它们,我会将以上所有值保留在预缓存中。但是当我们只需要它们一次捕获的图像时,开销可以忽略不计。
    • 不可能,customViewPosition 和 surfacePosition 始终为 0,0。我尝试了很多次,但值没有变化。如果它们为 0,0,则应用程序崩溃。
    • left =142, top=80,width=568, height=320 ---- 位图 imageCropped = Bitmap.createBitmap(imageOriginal, left, top, width, height, null, false);在此语句中崩溃并出现错误 - java.lang.IllegalArgumentException: x + width must be
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