【发布时间】:2011-11-18 17:21:15
【问题描述】:
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String id = cur.getString(
cur.getColumnIndex(ContactsContract.Contacts._ID));
String name = cur.getString(
cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (name.equals(selected) && Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor pCur = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " =?", new String[] {
id
}, null);
finalsend = ContactsContract.CommonDataKinds.Phone.NUMBER;
while (pCur.moveToNext()) {
}
pCur.close();
}
代码应该通过联系人查找与“选定”变量匹配的联系人,该变量似乎工作正常,但随后应该切换到ContactsContract.CommonDataKinds.Phone.CONTENT_URI,并通过匹配 ID 找到相同的联系人并给出我为该联系人保存的电话号码。
每次返回“Data1”时,我做错了什么?这可能是一个愚蠢的错误,但感谢您的帮助。
【问题讨论】:
标签: android contacts contactscontract