【发布时间】:2019-10-24 21:30:38
【问题描述】:
我有一个 ViewPager 和一个 TabLayout 包含 3 个片段。有时,当我(在ViewPager 的帮助下)扫过 3 个片段时,会抛出一个 IllegalArgumentException 并显示 片段已添加:...(索引 0 处的片段到请明确点)。由于错误日志仅显示与 FragmentManager 类有关而与我的 Fragment 类无关,这可能是什么问题?以下是我正在使用的适配器
import androidx.fragment.app.Fragment
import androidx.fragment.app.FragmentManager
import androidx.fragment.app.FragmentPagerAdapter
import androidx.fragment.app.FragmentStatePagerAdapter
data class TitledFragment(val fragment: Fragment, val title: CharSequence?)
/**
* Should be used when displaying more than 2 [Fragment]s in a view-pager otherwise use
* [FragmentViewPagerAdapter]
*/
@Suppress("KDocUnresolvedReference")
class FragmentStateViewPagerAdapter(
private val titledFragmentList: List<TitledFragment>,
fragmentManager: FragmentManager
) : FragmentStatePagerAdapter(fragmentManager, BEHAVIOR_RESUME_ONLY_CURRENT_FRAGMENT) {
private val tabCount = titledFragmentList.size
/**
* Selects the middle or first [Fragment] as the default selected [Fragment] from a list
* ([titledFragmentList]) of odd-numbered [Fragment]s and even-numbered [Fragment]s respectively.
* For example, a view-pager supposed to display 3 fragments ([titledFragmentList] = 3) will have
* it's default selected fragment position equal to 1(2nd [Fragment]) from the list whereas a
* view-pager supposed to display 2 fragments ([titledFragmentList] = 2) will have it's default
* selected fragment position equal to 0(1st [Fragment])
*/
val middleFragmentPosition: Int
get() = if (tabCount <= 0 || tabCount == 1) {
0
} else {
val fl = tabCount.toFloat() / 2
when {
tabCount % 2 == 0 -> fl.toInt() - 1
else -> fl.toInt()
}
}
override fun getPageTitle(position: Int): CharSequence? =
titledFragmentList[position].title ?: super.getPageTitle(position)
override fun getItem(position: Int): Fragment = titledFragmentList[position].fragment
override fun getCount(): Int = tabCount
}
/**
* Should be used when displaying less than 3 [Fragment]s in a view-pager otherwise use
* [FragmentStateViewPagerAdapter]
*/
@Suppress("KDocUnresolvedReference")
class FragmentViewPagerAdapter(
private val titledFragmentList: List<TitledFragment>,
fragmentManager: FragmentManager
) : FragmentPagerAdapter(fragmentManager, BEHAVIOR_RESUME_ONLY_CURRENT_FRAGMENT) {
private val tabCount = titledFragmentList.size
/**
* Selects the middle or first [Fragment] as the default selected [Fragment] from a list
* ([titledFragmentList]) of odd-numbered [Fragment]s and even-numbered [Fragment]s respectively.
* For example, a view-pager supposed to display 3 fragments ([titledFragmentList] = 3) will have
* it's default selected fragment position equal to 1(2nd [Fragment]) from the list whereas a
* view-pager supposed to display 2 fragments ([titledFragmentList] = 2) will have it's default
* selected fragment position equal to 0(1st [Fragment])
*/
val middleFragmentPosition: Int
get() = if (tabCount <= 0 || tabCount == 1) {
0
} else {
val fl = tabCount.toFloat() / 2
when {
tabCount % 2 == 0 -> fl.toInt() - 1
else -> fl.toInt()
}
}
override fun getPageTitle(position: Int): CharSequence? =
titledFragmentList[position].title ?: super.getPageTitle(position)
override fun getItem(position: Int): Fragment = titledFragmentList[position].fragment
override fun getCount(): Int = tabCount
}
【问题讨论】:
-
middleFragmentPosition很容易简化,不使用。
标签: android-fragments kotlin android-viewpager androidx fragmentmanager